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\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).....\left(1-\frac{1}{100}\right).200x=4036\)
\(\Leftrightarrow\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{99}{100}.200x=4036\)
\(\Leftrightarrow\frac{1.2.3...99}{2.3.4....100}.200x=4036\)
\(\Leftrightarrow\frac{1}{100}.200x=4036\)
\(\Leftrightarrow\frac{1}{100}.200x=4036\)
\(\Leftrightarrow2x=4036\)
\(\Leftrightarrow x=4036:2=2018\)
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times...\times\left(1-\frac{1}{100}\right)\times200\times x=4036\)
=> \(\frac{1}{2}\times\frac{2}{3}\times...\times\frac{99}{100}\times200\times x=4036\)
=> \(\frac{1\times2\times...\times99}{2\times3\times...\times100}\times200\times x=4036\)
\(\Rightarrow\frac{1}{100}\times200\times x=4036\)
\(\Rightarrow2\times x=4036\)
=> x = 2018
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a) \(5\times\left(3+7\times x\right)=400\)
\(3+7\times x=80\)
\(7\times x=77\)
\(x=11\)
b) \(x\times37+x\times63=1200\)
\(x\times\left(37+63\right)=1200\)
\(x\times100=1200\)
\(x=12\)
c) \(x\times6+12:3=40\)
\(x\times6+4=40\)
\(x\times6=36\)
\(x=6\)
d) \(4+6\times\left(x+1\right)=70\)
\(6\times\left(x+1\right)=66\)
\(x+1=11\)
\(x=10\)
e) \(163:x+34:x=10\)
\(\left(163+34\right):x=10\)
\(197:x=10\)
\(x=19,7\)
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Mình làm cách lớp 6 nha bạn, cách lớp 4 mình không biết.
\(\frac{1}{2}.x+\frac{1}{5}.x=\frac{2}{5}\)
\(\Rightarrow x.\left(\frac{1}{2}+\frac{1}{5}\right)=\frac{2}{5}\)
\(\Rightarrow x.\frac{7}{10}=\frac{2}{5}\)
Giờ thành tìm x rồi!
\(x=\frac{7.5}{2.10}\)
\(x=1\frac{3}{4}\)
Xong!
\(\frac{1}{2}\times x+\frac{1}{5}\times x=\frac{2}{5}\)
\(x\times\left(\frac{1}{2}+\frac{1}{5}\right)=\frac{2}{5}\)
\(x\times\frac{7}{10}=\frac{2}{5}\)
\(x=\frac{2}{5}:\frac{7}{10}\)
\(x=\frac{4}{7}\)
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a) 5 × x + 3 × x =1096
x × ( 5 + 3 ) = 1096
x × 8 = 1096
x = 1096 :8
x = 137
b) 189 : x - 37 : x=8
( 189 - 37 ) : x = 8
152 : x = 8
x = 152 : 8
x = 19
ủng hộ nha
a , 5 X x + 3 X x = x X ( 5+3 ) = x X 8 = 1096
=> x = 1096 : 8 = 137.
b , 189 : x - 37 : x = ( 189-37 ) : x = 152 : x = 8
=> x = 152 : 8 = 19.
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\(\Rightarrow x\times\left(\frac{1}{2}+\frac{3}{2}\right)=\frac{4}{5}\)
\(\Rightarrow x\times\frac{4}{2}=\frac{4}{5}\)
\(\Rightarrow x\times2=\frac{4}{5}\)
\(\Rightarrow x=\frac{4}{5}\div2\)
\(\Rightarrow x=\frac{4}{5}\times\frac{1}{2}\)
\(\Rightarrow x=\frac{2}{5}\)
\(x\times\frac{1}{2}+\frac{3}{2}\times x=\frac{4}{5}\)
\(x\times\left(\frac{1}{2}+\frac{3}{2}\right)=\frac{4}{5}\)
\(x\times2=\frac{4}{5}\)
\(x=\frac{4}{5}:2\)
\(x=\frac{2}{5}\)
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a) 3045 + 1634 - 1045 + 1366
= ( 3045 - 1045 ) + ( 1634 + 1366 )
= 2000 + 3000
= 5000
b) 24 x 5 + 24 x 3 + 24 x 2
= 24 x ( 5 + 3 + 2 )
= 24 x 10
= 240
c) 653 x 99
= 653 x 100 - 653
= 65300 - 653
= 64647
d) 165 x 12 + 165 x 17 + 165
= 165 x (12 + 17 + 1)
= 165 x 30
= 4950
e) 98 x 8 + 98 x 13 - 98
= 98 x ( 8 + 13 - 1 )
= 98 x 20
= 1960
f) 125 x 63 x 8
= 125 x 8 x 63
= 1000 x 63
= 63000
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100x(43x10+43-2x43x5)+500
=100x(43x11-43x10)+500
=100x[43x(11-10)]+500
=100x43+500
=4300+500
=4800
100(43.10+43-2.43.5)+500
=100(430+43-430)+500
=100.43+500
=4300+500
=4800
x\(\times\)(5+2+3)=100
x\(\times\)10=100
x=100\(\div\)10=10
Vậy x =10
\(\left(x\times5\right)+\left(x\times2\right)+\left(x\times3\right)=100\)
=> \(x\times\left(5+3+2\right)=100\)
=> \(x\times10=100\)
=> \(x=100\div10=10\)