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\(\left[x-\frac{1}{2}\right]\left[1+5x\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{2}=0\\1+5x=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\5x=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-\frac{1}{5}\end{cases}}\)
Vậy : ....
Th1:
x-1/2=0
x =0+1/2
x =1/2
Th2:
1+ 5x=0
5x=0-1
5x=-1
x=-1:5
x=-1/5
hok tốt!!!
\(\left(x+1\right)\left(x+7\right)< 0\)
thì \(x+1;x+7\)khác dấu
th1\(\hept{\begin{cases}x+1< 0\\x+7>0\end{cases}\Leftrightarrow\hept{\begin{cases}x< -1\\x>-7\end{cases}\Rightarrow}-7< x< -1\left(tm\right)}\)
th2\(\hept{\begin{cases}x+1>0\\x+7< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x>-1\\x< -7\end{cases}\Rightarrow}-1< x< -7\left(vl\right)}\)
vậy với\(-7< x< -1\)thì \(\left(x+1\right)\left(x+7\right)< 0\)
a) (2x - 3) = 5
<=> 2x - 3 = 5
<=> 2x = 5 + 3
<=> 2x = 8
<=> x = 4
=> x = 4
b) (5x - 3) = 1/2
<=> 5x - 3 = 1/2
<=> 5x = 1/2 + 3
<=> 5x = 7/2
<=> x = 7/10
=> x = 7/10
c) (x + 1)(x + 7) < 0
<=> x = -1; -7
<=> x < -7 <=> x = -8 <=> (-8 + 1)(-8 + 7) < 0 <=> 7 < 0 (loại)
<=> -7 < x < -1 <=> x = -6 <=> (-6 + 1)(-6 + 7) < 0 <=> -5 < 0 (nhận)
<=> x > -1 <=> x = 0 <=> (x + 1)(x + 7) < 0 <=> 7 < 0 (loại)
Vậy: -7 < x < -1
a) 3x - 2 = 0 => 3x = 2 => x = 2/3
b) 2x - 1 = 0 => 2x = 1 => x = 1/2
c) 5 ( 4+2x) = 8+5x
<=> 20 + 10x = 8 + 5x
<=> 10x - 5x = 8 - 20
<=> 5x = -12
x = -12/5
d) \(\frac{1}{2}+\frac{3}{4}x=6-\frac{4}{5}x\)
\(\frac{3}{4}x+\frac{4}{5}x=6-\frac{1}{2}\)
\(\frac{31}{20}x=\frac{11}{2}\)
\(x=\frac{11}{2}:\frac{31}{20}=\frac{110}{31}\)
e) 3 + 2x = 4 - 8x
<=> 2x + 8x = 4 - 3
10 x = 1
x = 1/10
f \(5+\frac{1}{2}\left(x+5\right)=3\)
\(\frac{1}{2}\left(x+5\right)=3-5=-2\)
\(x+5=-2:\frac{1}{2}=-4\)
\(x=-4-5=1\)
Vậy ......
Ta có : \(\left(5x-3\right)\left(2x+5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}5x-3=0\\2x+5=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}5x=3\\2x=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}\\x=-\frac{5}{2}\end{cases}}\)
A, số nguyên âm lớn nhất là -1
=> 10-x=-1
X= 10 - (-1)
X= 11
B, |x-1| = |-4|
TH1: x-1=-4
X = -4 + 1
X = -3
TH2: x-1 = 4
X = 4+1
X = 5
Mình làm vật thôi ^_^ chúc bạn học tốt
Đức™
🤟🏿🤟🏿🤟🏿🤟🏿🤟🏿🌹
a/ 10-x là số nguyên âm lớn nhất => 10-x=-1
=>x=11
b/ I x-1 I =I-4I
=> Ix-1I=4 =>x-1=4 hoặc x-1=-4
=> x= 5 hoặc x= -3
c/(4-61-19x).(-4)2 =0 => -57-19x=0
=> 19x=-57 => x=-3
d/ 5x/-12=1/4+3/-2
=> 5x/-12=5/-12
=> 5x=5 => x=1
a/\(5x\cdot\left(x-\frac{1}{3}\right)=0\)
Chia làm 2 TH :
TH 1: \(5x=0\Rightarrow x=0\)
TH 2:\(x-\frac{1}{3}=0\Rightarrow x=\frac{1}{3}\)
\(\Rightarrow x\in\left\{0;\frac{1}{3}\right\}\)
b/\(\left(x+\frac{1}{4}\right)\cdot\left(x-\frac{3}{7}\right)=0\)
Chia làm 2 Th
Th1 : \(x+\frac{1}{4}=0\Rightarrow x=-\frac{1}{4}\)
Th2 :\(x-\frac{3}{7}=0\Rightarrow x=\frac{3}{7}\)
\(\Rightarrow x\in\left\{-\frac{1}{4};\frac{3}{7}\right\}\)
1) \(5x\left(x-\frac{1}{3}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}5x=0\\x-\frac{1}{3}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{3}\end{cases}}\)
2) \(\left(x+\frac{1}{4}\right)\left(x-\frac{3}{7}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{4}=0\\x-\frac{3}{7}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{4}\\x=\frac{3}{7}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{4}\\x=\frac{3}{7}\end{cases}}\)
( 5x - 1 ).( 2 x - \(\frac{1}{3}\)) = 0
\(\Rightarrow\)5x - 1 = 0 hay 2x - \(\frac{1}{3}\)= 0
TH 1 : 5x - 1 = 0
5x = 1 => x = \(\frac{1}{5}\)
TH 2 :
2x - \(\frac{1}{3}\) = 0
2x = \(\frac{1}{3}\)
x = \(\frac{1}{3}\): 2 = \(\frac{1}{6}\)
\(\Rightarrow\)\(\orbr{\begin{cases}5x-1=0\\2x-\frac{1}{3}=0\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}5x=1\\2x=\frac{1}{3}\end{cases}}\)
\(\Rightarrow\)\(\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{6}\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{6}\end{cases}}\)
(2x-3)( 3/4x+1) = 0
=> 2x-3= 0 hoặc 3/4x +1 = 0
=> 2x= 3 hoặc 3/4x = -1
=> x=3/2 hoặc x= -4/3
(5x-1)(2x-1/3) = 0
=> 5x-1 = 0 hoặc 2x-1/3 = 0
5x =1 hoặc 2x=1/3
x=1/5 hoặc x= 1/6
\(\left(x-\frac{1}{2}\right).\left(1+5x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{2}=0\\1+5x=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0+\frac{1}{2}\\5x=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\left(-1\right):5\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-\frac{1}{5}\end{cases}}\)
Vậy \(x\in\left\{\frac{1}{2};-\frac{1}{5}\right\}.\)
Chúc bạn học tốt!
\(\left(x-\frac{1}{2}\right)\left(1+5x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=0\\1-5x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\5x=1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{1}{5}\end{cases}}}\)
Vậy x={\(\frac{1}{2};\frac{1}{5}\)}