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(7x-11)3=25.52+200
(7x-11)3=32.25+200
(7x-11)3=800+200
(7x-11)3=1000
(7x-11)3=103
=> 7x-11=10
7x=10+11
7x=21
x=21/7
x=3
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x - 6 : 2 ( 48 - 24 ) : 2 : 6 - 3 = 0
x - 6 : 2 . 24 : 2 : 6 - 3 = 0
x - 6 - 3 = 0
x - 9 = 0
x = 9
x-6:2 ( 48-24) :2 :6 - 3 = 0
=>x-6:2(48-24):2:6= 3
=> x-6:2(48-24):2 = 18
=> x-6:2(48-24)= 36
=> x- 6:2. 24= 36
=> x- 6: 48= 36
=>x +8=36
=> x= 36-8
=>x= 28
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Dấu \(\Rightarrow\) thứ nhất phải là -46x, bạn làm sai dấu rồi.
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\(\frac{x+11}{x+2}\in N\)
\(\Rightarrow\left(x+11\right)⋮\left(x+2\right)\)
\(\Rightarrow\left(x+2+9\right)⋮\left(x+2\right)\)
Vì \(x+2⋮x+2\Rightarrow9⋮\left(x+2\right)\)
\(\Rightarrow\left(x+2\right)\in\left(1;3;9\right)\)
Vì x thuộc N \(\Rightarrow n\in\left(1;7\right)\)
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Bài 2 :
a) 34 + ( 9 - 21 ) =2017 - (x +2017)
34 + 9 - 21 =2017 - x -2017
22=-x
x=-22
b) (15-x)+(x-12) =7-(-8+x)
15-x+x-12 =7+8-x
3=15-x
x=12
c) x-(11-x) = - 48 + (-12 + x
x-11+x = - 48 -12 + x
2x-11=-60+x
2x-x=-60+11
x=-49
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 7:
a, \(x\) = \(\dfrac{1}{5}\) + \(\dfrac{2}{11}\)
\(x\) = \(\dfrac{11}{55}\) + \(\dfrac{10}{55}\)
\(x=\dfrac{21}{55}\)
b, \(\dfrac{x}{15}\) = \(\dfrac{3}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{x}{15}\) = \(\dfrac{9}{15}\) - \(\dfrac{10}{15}\)
\(\dfrac{x}{15}\) = \(\dfrac{1}{15}\)
\(x\) = 1
c, \(\dfrac{11}{8}\) + \(\dfrac{13}{6}\)= \(\dfrac{85}{x}\)
\(\dfrac{33}{24}\) + \(\dfrac{52}{24}\) = \(\dfrac{85}{x}\)
\(\dfrac{85}{24}\) = \(\dfrac{85}{x}\)
24 = \(x\)
x – (11 – x) = -48 + (-12 + x)
=> x−11+x=−48+−12+x
=> −11+x=−48−12
=> -11+x=-60
=> x=-49
Vậy x=-49
\(x-\left(11-x\right)=-48+\left(-12+x\right)\)
\(\Leftrightarrow x-11+x=-48-12+x\)
\(\Leftrightarrow x=-49\)
Vậy x = -49