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Lời giải:
\(x^6-9x^5+30x^4-45x^3+30x^2-9x+1\)
\(=(x^2)^3-3.(x^2)^2.(3x)+3.x^2(3x)^2-(3x)^3+3x^4-18x^3+30x^2-9x+1\)
\(=(x^2-3x)^3+3x^4-18x^3+30x^2-9x+1\)
\(=(x^2-3x)^3+3(x^4-6x^3+9x^2)+3x^2-9x+1\)
\(=(x^2-3x)^3+3(x^2-3x)^2+3(x^2-3x)+1\)
\(=(x^2-3x+1)^3\)
\(9x^2+6x-4y^2+4y=\left(9x^2+6x+1\right)-\left(4y^2-4y+1\right)=\left(3x+1\right)^2-\left(2y-1\right)^2=\left(3x+1-2y+1\right)\left(3x+1+2y-1\right)\)
1: \(x^2-2x-24=\left(x-6\right)\left(x+4\right)\)
2: \(x^2-8x+15=\left(x-3\right)\left(x-5\right)\)
3: \(x^2-9x+14=\left(x-2\right)\left(x-7\right)\)
x4 - 30x2 + 31x - 30
= x4 + x - 30x2 + 30x - 30
= x(x3 + 1) - 30(x2 - x + 1)
= x(x + 1)(x2 - x + 1) - 30(x2 - x + 1)
= (x2 - x + 1)[x(x + 1) - 30]
= (x2 - x + 1)(x2 + x - 30)
= (x2 - x + 1)(x2 - 5x + 6x - 30)
= (x2 - x + 1)[x(x - 5) + 6(x - 5)]
= (x2 - x + 1)(x - 5)(x + 6)
a) x^2-9x+20
= x^2+4x+5x+20
=(x^2+4x)+(5x+20)
=x(x+4)+5(x+4)
=(x+4)(x+5)
\(x^6-9x^5+30x^4-45x^3+30x^2-9x+1\)
\(=\left(x^2\right)^3-9x^5+30x^4-45x^3+30x^2-9x+1^3\)
\(=\left(x^3-3x+1\right)^3\)