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Khách

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5 tháng 10 2019

1-\(\left(3\frac{3}{8}+x-2\frac{5}{24}\right)\)\(.\frac{12}{17}=0\)

\(\Rightarrow\left(3\frac{3}{8}+x-2\frac{5}{24}\right)\)\(.\frac{12}{17}\)\(=1\)

            \(\frac{27}{8}+x-\frac{53}{24}\)              \(=1:\frac{12}{17}\)

           \(\frac{27}{8}+x=\frac{17}{12}+\frac{53}{24}\)

           \(\frac{27}{8}+x=\frac{34+53}{24}\)

           \(\frac{27}{8}+x=\frac{87}{24}\)

                         \(x=\frac{87}{24}-\frac{27}{8}\)

                        \(x=\frac{87-81}{24}\)

                       \(x=\frac{6}{24}=\frac{1}{4}\)

3 tháng 7 2018

Câu b:

\(\frac{21}{8}:\frac{5}{6}+\frac{1}{2}:\frac{5}{6}\)

\(\frac{63}{20}+\frac{3}{5}\)

\(\frac{15}{4}\)

7 tháng 7 2018

\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)

\(\frac{25}{8}:\frac{5}{6}\)

\(\frac{25}{8}.\frac{6}{5}\)

\(\frac{30}{8}\)

16 tháng 8 2017

Ta có:

\(A=\left(x-\frac{1}{2}\right).\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)=\frac{1}{3}\)

\(\Leftrightarrow A=\left(x-\frac{1}{2}\right).\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)=\frac{1}{3}\)

\(\Leftrightarrow A=\left(x-\frac{1}{2}\right).\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)=\frac{1}{3}\)

\(\Leftrightarrow A=\left(x-\frac{1}{2}\right).\left(\frac{1}{1}-\frac{1}{10}\right)=\frac{1}{3}\)

\(\Leftrightarrow A=\left(x-\frac{1}{2}\right).\frac{9}{10}=\frac{1}{3}\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}.\frac{10}{9}\Leftrightarrow x=\frac{47}{54}\)

\(B=\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+...+\frac{1}{96.101}=\frac{1}{10.x}\)

\(\Leftrightarrow B=\frac{1}{5}.\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{96.101}\right)=\frac{1}{10}-\frac{1}{x}\)

\(\Leftrightarrow B=\frac{1}{5}.\left(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{96}-\frac{1}{101}\right)=\frac{1}{10}-\frac{1}{x}\)

\(\Leftrightarrow B=\frac{1}{5}.\left(\frac{1}{1}-\frac{1}{101}\right)=\frac{1}{10}-\frac{1}{x}\Leftrightarrow B=\frac{1}{5}.\frac{100}{101}=\frac{1}{10}-\frac{1}{x}\)

\(\Leftrightarrow B=\frac{1}{x}=\frac{1}{10}-\frac{20}{101}=-\frac{99}{1010}\Leftrightarrow x=-\frac{1010}{99}\)

16 tháng 8 2017

c) Sai đề nhé bạn vì không có kết quả nên không tìm được x.

d) \(\left(x-5\right).\left(10-9\frac{40}{41}\right):\left(1-\frac{81}{82}\right):\left(1-\frac{204}{205}\right)=2050\)

\(\Rightarrow\left(x-5\right).\frac{1}{41}.82.205=2050\)

\(\Rightarrow\left(x-5\right).2.205=2050\Leftrightarrow x-5=2050:410=5\Leftrightarrow x=10\)

25 tháng 7 2015

(15/4.4-12/5.5/4)-(7/2:5/2-1/5)-1/5.x=51/5

(15-3)-(7/5-1/5)-1/5.x=51/5

12-6/5-1/5.x=51/5

54/5-1/5.x=51/5

        1/5x=54/5-51/5

         1/5x=3/5

             x=3

\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

\(\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)

\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}\)

\(\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}\)

\(\Rightarrow\frac{43}{8}+x=\frac{199}{8}\)

\(\Rightarrow x=\frac{199}{8}-\frac{43}{8}\)

\(\Rightarrow x=\frac{156}{8}=\frac{39}{2}\)

24 tháng 3 2019

\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)

\(< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)

\(< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)

\(< =>\frac{43}{8}+x-\frac{173}{24}=0\)

\(< =>\frac{43}{8}+x=\frac{173}{24}\)

\(< =>x=\frac{173}{24}-\frac{43}{8}\)

\(< =>x=\frac{11}{6}\)

23 tháng 6 2015

1, \(\frac{1}{2}-\left(6\frac{5}{9}+x-\frac{117}{8}\right):\left(12\frac{1}{9}\right)=0\)

   \(\left(\frac{6.9+5}{9}+x-\frac{117}{8}\right):\frac{12.9+1}{9}=\frac{1}{2}\)

 ( . là nhân nha) 

    \(\left(\frac{59}{9}-\frac{117}{8}+x\right):\frac{109}{9}=\frac{1}{2}\)

    \(\frac{59}{9}-\frac{117}{8}+x=\frac{1}{2}\cdot\frac{109}{9}\)

    \(\frac{59}{9}-\frac{117}{8}+x=\frac{109}{18}\)

   \(x=\frac{109}{18}-\frac{59}{9}+\frac{117}{8}\)

\(x=\frac{113}{8}\)

23 tháng 6 2015

\(\left(y+\frac{1}{3}\right)+\left(y+\frac{2}{9}\right)+\left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)

   \(y+\frac{1}{3}+y+\frac{2}{9}+y+\frac{1}{27}+y+\frac{1}{81}=\frac{56}{81}\)

\(4y+\frac{1}{3}+\frac{2}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)

\(4y+\frac{49}{81}=\frac{56}{81}\)

\(4y=\frac{7}{81}\)

y      =  7/81:4

y       = 7/324

23 tháng 1 2016

(1-1/2).(1-1/3).(1-1/4).(1-1/5)=b/100

=> 1/2.2/3.3/4.4/5=b/100

=> 1/5=b/100

=> b=100:5=20

20 tháng 9 2015

\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\)\(:16\frac{2}{3}=0\)

\(\Rightarrow\)\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)=0\)

\(\Rightarrow\)\(5\frac{3}{8}+x-7\frac{5}{24}=2\)

\(\Rightarrow5\frac{3}{8}+x=9\frac{5}{24}\)

\(\Rightarrow x=3\frac{5}{6}\)

( Cách làm thì đúng rồi nhưng đáp án tớ ko chắc chắn )

23 tháng 1 2016

Chỉ biết \(x\) = \(\frac{109}{6075}\) thôi