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\(x\) ⋮ 12; \(x\)⋮ 16; \(x\) ⋮ 10; \(x\) ⋮ 14 và \(x\) nhỏ nhất
⇒ \(x\) là BCNN của (12;16;10;14)
12 = 22.3; 16 = 24; 10 = 2.5; 14 = 2.7
BCNN(12; 16; 10;14) = 24.3.5.7 = 1680
\(x\) = 1680
\(\)\(\left\{{}\begin{matrix}x⋮12;x⋮10;x⋮16;x⋮14\\x\left(min\right)\end{matrix}\right.\)
\(\Rightarrow x\in BCNN\left(10;12;14;16\right)=2^4.3.5.7=1680\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a: BCNN(10;12)=60
b: BCNN(24;10)=120
c: BCNN(4;14;26)=364
d: BCNN(6;8;10)=120
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(5\times x-123=12\)
\(\Rightarrow5\times x=135\)
\(\Rightarrow x=27\)
b) \(x+3x+5x+7x=96\)
\(\Rightarrow16x=96\)
\(\Rightarrow x=6\)
a) \(5\times x-123=12\)
\(5x=12+123\)
\(5x=135\)
\(x=135:5\)
\(x=27\)
________
b) \(x+3x+5x+7x=96\)
\(x\left(1+3+5+7\right)=96\)
\(x.16=96\)
\(x=96:16\)
\(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, x : 12 = 27
=> x = 27.12 = 324
Vậy x = 324
b, 1414 : x = 14
=> x = 1414 : 14 = 101
Vậy x = 101
c, 5x : 12 = 0
=> 5x = 0
=> x = 0.
Vậy x = 0
d, 0 : x = 0
∀ x ∈ ¥, x≠0
![](https://rs.olm.vn/images/avt/0.png?1311)
a: ta có: \(12⋮x+3\)
\(\Leftrightarrow x+3\in\left\{3;4;6;12\right\}\)
hay \(x\in\left\{0;1;3;9\right\}\)
b: Ta có: \(14⋮2x\)
\(\Leftrightarrow2x\in\left\{2;14\right\}\)
hay \(x\in\left\{1;7\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(x\inƯC\left(180;96\right)\)
mà x>8
nên x=12
b: \(x\in UC\left(150;84;30\right)\)
mà 0<x<10
nên \(x\in\left\{1;2;3;6\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
SSH = (98 - 10) : 2 + 1 = 45 (SH)
Tổng = (98 + 10) / 2 x 45 = 2430
45x + 2430 = 2520
45x = 90
x = 2