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15: A= 1/3-3/4+3/5+1/2007-1/36+1/15-2/9
Sửa đề:
A=-3/4-2/9-1/36+1/3+3/5+1/15+1/2007
=-27/36-8/36-1/36+5/15+9/15+1/15+1/2007
=-1+1+1/2007=1/2007
16:
\(A=\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}-\dfrac{3}{4}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{64}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-8-1}{36}+\dfrac{1}{64}\)
=1/64
17:
=1/2-1/2+2/3-2/3+3/4-3/4+4/5-4/5+5/6-5/6-6/7
=-6/7
\(\frac{3^{11}\div5+3^{11}.3}{3^{10}.2^2}=\frac{3^{11}\cdot\frac{1}{5}+3^{11}\cdot3}{3^{10}.2^2}\)
\(=\frac{3^{11}.\left(\frac{1}{5}+3\right)}{3^{10}.2^2}=\frac{3^{11}.\frac{16}{5}}{3^{10}.2^2}=\frac{\frac{48}{5}}{2^2}=\frac{48}{5}\cdot\frac{1}{4}=\frac{12}{5}\)
\(\frac{1}{3^{10}}\div\frac{1}{9^5}=\frac{1}{3^{10}}\div\frac{1}{3^{10}}=1\)
1:
a: =7/5(40+1/4-25-1/4)-1/2021
=21-1/2021=42440/2021
b: =5/9*9-1*16/25=5-16/25=109/25
1: \(\dfrac{11}{24}-\dfrac{5}{41}+\dfrac{13}{24}+0,5-\dfrac{36}{41}\)
\(=\left(\dfrac{11}{24}+\dfrac{13}{24}\right)-\left(\dfrac{5}{41}+\dfrac{36}{41}\right)+\dfrac{1}{2}\)
\(=1-1+\dfrac{1}{2}=\dfrac{1}{2}\)
2: \(12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
\(=12:\left(\dfrac{9}{12}-\dfrac{10}{12}\right)^2\)
\(=12:\left(-\dfrac{1}{12}\right)^2=12:\dfrac{1}{144}=12\cdot144=1368\)
3: \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\left(0,8-\dfrac{3}{4}\right)^2\)
\(=\dfrac{12+8-3}{12}\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{17}{12}\cdot\left(\dfrac{16-15}{20}\right)^2\)
\(=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\)
4: \(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\dfrac{5}{3}\cdot\left(-16-\dfrac{2}{7}\right)+\dfrac{5}{3}\cdot\left(28+\dfrac{2}{7}\right)\)
\(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\)
\(=12\cdot\dfrac{5}{3}=20\)
5: \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}\cdot\dfrac{6}{5}-17=3-17=-14\)
6: \(\left(\dfrac{1}{3}\right)^{50}\cdot\left(-9\right)^{25}-\dfrac{2}{3}:4\)
\(=\left(\dfrac{1}{3}\right)^{50}\cdot\left(-1\right)\cdot3^{50}-\dfrac{2}{3\cdot4}\)
\(=-1-\dfrac{2}{12}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
Câu 1 :So Sánh
\(3^{34}\text{và }5^{20}\)
\(\Leftrightarrow3^{34}>5^{20}\)
Câu 2 : Tìm chữ số tận cùng
\(3^{25}\text{có tận cùng là 3}\)
\(9^{27}\text{có tận cùng là 9}\)
Học tốt
#)Giải :
Câu 2 :
Ta có : \(\frac{1}{9^5}=\frac{1}{\left(3^2\right)^5}=\frac{1}{3^{10}}\)
Vì \(\frac{1}{3^5}=\frac{1}{3^5}\Rightarrow\frac{1}{3^5}=\frac{1}{9^5}\)
311:5+311 .3/310.22(Câu 1)
\(=\frac{8.3^{11}}{3^{10}.4}=6\)
1/310 : 1/95 (Câu 2)
\(=\frac{1}{3^{10}}.3^{10}=1\)
(-25/36)5:5/62 (câu 3)
\(=\frac{-5^5}{6^{10}}.\frac{6^2}{5}=-\frac{5^4}{6^8}\)