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VT
1
AM
14 tháng 6 2015
a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)
b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)
VN
Võ Ngọc Phương
CTVHS
VIP
18 tháng 7 2023
\(\dfrac{11}{49}\times\dfrac{1}{2}+\dfrac{11}{49}:\dfrac{5}{4}-\dfrac{11}{49}\times\dfrac{3}{4}\)
\(=\dfrac{11}{49}\times\dfrac{1}{2}+\dfrac{11}{49}\times\dfrac{4}{5}-\dfrac{11}{49}\times\dfrac{3}{4}\)
\(=\dfrac{11}{49}\times\left(\dfrac{1}{2}+\dfrac{4}{5}-\dfrac{3}{4}\right)\)
\(=\dfrac{11}{49}\times\left(\dfrac{10}{20}+\dfrac{16}{20}-\dfrac{15}{20}\right)\)
\(=\dfrac{11}{49}\times\dfrac{11}{20}\)
\(=\dfrac{121}{980}\)
Chúc bạn học tốt
18 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{11}{49}\times\dfrac{1}{2}+\dfrac{11}{49}\div\dfrac{5}{4}-\dfrac{11}{49}\times\dfrac{3}{4}\)
`=`\(\dfrac{11}{49}\times\dfrac{1}{2}+\dfrac{11}{49}\times\dfrac{4}{5}-\dfrac{11}{49}\times\dfrac{3}{4}\)
`=`\(\dfrac{11}{49}\times\left(\dfrac{1}{2}+\dfrac{4}{5}-\dfrac{3}{4}\right)\)
`=`\(\dfrac{11}{49}\times\dfrac{11}{20}\)
`=`\(\dfrac{121}{980}\)
12 tháng 8 2018
\(\frac{1}{11}+\frac{2}{11}+\frac{3}{11}+\frac{4}{11}+...+\frac{10}{11}\)
\(=\frac{1+2+3+4+...+10}{11}\)
\(=\frac{\frac{10\times\left(10+1\right)}{2}}{11}\)
\(=\frac{55}{11}=5\)
DA
12 tháng 8 2018
\(\frac{1}{11}+\frac{2}{11}+\frac{3}{11}+\frac{4}{11}+...+\frac{10}{11}=\frac{1+2+3+4+...+10}{11}=\frac{55}{11}=5\)
TP
6 tháng 8 2017
Ta có:
\(A=\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(A=\frac{1}{3}-\frac{1}{15}=\frac{4}{15}\)
\(B=2.\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right)\)
\(B=2.\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(B=2.\left(\frac{1}{1}-\frac{1}{10}\right)=2.\frac{9}{10}\)
\(B=\frac{9}{5}\)
TT
4
15 tháng 5 2018
=(1/11+10/11)+(2/11+9/11)+(3/11+8/11)+(4/11+7/11)+(5/11+6/11)
=11/11+11/11+11/11+11/11+11/11
=1+1+1+1+1
=5
ND
Nguyễn Đức Trí
VIP
14 tháng 8 2023
a) \(...\Rightarrow x.\left(2+5\right)=14\Rightarrow x.7=14\Rightarrow x=14:7=2\)
b) \(...\Rightarrow x.\left(9+1\right)=20\Rightarrow x.10=20\Rightarrow x=20:10=2\)
c) \(...\Rightarrow x.\left(\dfrac{2}{3}+\dfrac{1}{3}\right)=1999\Rightarrow x.\dfrac{3}{3}=1999\Rightarrow x=1999\)
d) \(...\Rightarrow11.x+22=5.x+40\Rightarrow11.x-5.x=40-22\Rightarrow6.x=18\Rightarrow x=18:6=3\)
e) \(...\Rightarrow11.x-66=4.x+11\Rightarrow11.x-4.x=11+66\Rightarrow7.x=77\Rightarrow x=77:7=11\)
f) \(...\Rightarrow\left(3.x-12\right):x=12-10\)
\(\Rightarrow3.x-12=2.x\)
\(\Rightarrow3.x-2.x=12\)
\(\Rightarrow x=12\)
g) \(...\Rightarrow\left(5.x+7\right):x=26-20\)
\(\Rightarrow5.x+7=6.x\)
\(\Rightarrow6.x-5.x=7\)
\(\Rightarrow x=7\)
h) \(...\Rightarrow x.\left(1999-1\right)=1999.\left(1997+1\right)\)
\(\Rightarrow x.1998=1999.1998\)
\(\Rightarrow x=1999.1998:1998\)
\(\Rightarrow x=1999\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 8 2023
a, \(x\times\) 2 + \(x\times\) 5 = 14
\(x\) \(\times\) ( 2 + 5) = 14
\(x\) \(\times\) 7 = 14
\(x\) = 14: 7
\(x\) = 2
b, \(x\times9\) + \(x\)= 20
\(x\) \(\times\)( 9 + 1) = 20
\(x\) \(\times\) 10 = 20
\(x\) = 2
c, \(x\) : \(\dfrac{3}{2}\) + \(x\times\dfrac{1}{3}\) = 1999
\(x\times\) \(\dfrac{2}{3}\) + \(x\) \(\times\dfrac{1}{3}\) = 1999
\(x\times\) ( \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) = 1999
\(x\) = 1999
d, 11\(\times\)(\(x+2\)) = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) + 22 = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 40 - 22
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 18
11 \(\times\) \(x\) - 5 \(\times\) \(x\) = 18
\(x\) \(\times\) ( 11 - 5) = 18
\(x\) \(\times\) 6 = 18
\(x\) = 3
4/7 * 5/11 + 4/7 * 6/11+ (-2/3) = 4/7 * (5/11 + 6/11) + (-2/3)
= 4/7 *1 + (-2/3)
= 4/7 + (-2/3)
= -2/21
\(\frac{4}{7}.\frac{5}{11}+\frac{4}{7}.\frac{6}{11}+\frac{-2}{3}\)
=\(\frac{4}{7}.\left(\frac{5+6}{11}\right)+\frac{-2}{3}\)
=\(\frac{4}{7}.1+\frac{-2}{3}\)
=\(\frac{4}{7}+\frac{-2}{3}\)
=\(\frac{-2}{21}\)
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