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y x 3/7 = 13/15 - 2/5
y x 3/7 = 7/15
y = 7/15 : 3/7
y = 49/45
Vậy y = 49/45
\(Y\cdot\frac{3}{7}=\frac{13}{15}-\frac{2}{5}\)
=>\(Y\cdot\frac{3}{7}=\frac{7}{15}\)
=>\(Y=\frac{7}{15}:\frac{3}{7}=\frac{49}{45}\)
( dấu . là * đó)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}+\frac{2}{11\cdot13}+\frac{2}{13\cdot15}\)
\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{13}-\frac{1}{15}=1-\frac{1}{15}=\frac{14}{15}\)
Bài làm:
Ta có: \(A=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(A=1-\frac{1}{15}\)
\(A=\frac{14}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{14}{18}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
y = \(\dfrac{7}{9}\) : \(\dfrac{13}{15}\)
y = \(\dfrac{35}{39}\)
thử lại ta có:
\(\dfrac{35}{39}\) \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
\(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\) = \(\dfrac{7}{9}\)
Vậy y = \(\dfrac{35}{39}\) là đúng
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{4}{7}+\dfrac{7}{2}\\ =\dfrac{8}{14}+\dfrac{49}{14}\\ =\dfrac{8+49}{14}\\ =\dfrac{57}{14}\)
\(b,\dfrac{5}{8}\times\dfrac{3}{2}\\ =\dfrac{5\times3}{8\times2}\\ =\dfrac{15}{16}\)
\(c,\dfrac{3}{2}\times\dfrac{5}{6}-\dfrac{2}{3}\\ =\dfrac{3\times5}{2\times6}-\dfrac{2}{3}\\ =\dfrac{15}{12}-\dfrac{2}{3}\\ =\dfrac{15}{12}-\dfrac{8}{12}\\ =\dfrac{15-8}{12}\\ =\dfrac{7}{12}\)
\(d,\dfrac{13}{15}+\dfrac{2}{5}:\dfrac{3}{4}\\ =\dfrac{13}{15}+\dfrac{2}{5}\times\dfrac{4}{3}\\ =\dfrac{13}{15}+\dfrac{2\times4}{5\times3}\\ =\dfrac{13}{15}+\dfrac{8}{15}\\ =\dfrac{13+8}{15}\\ =\dfrac{21}{15}\\ =\dfrac{7}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`3/7 + 4/5 + 4/7`
`= (3/7 +4/7)+4/5`
`= 7/7 +4/5`
`= 1 + 4/5`
`= 5/5 +4/5`
`=9/5`
`------`
`6/11 + 2/15 + 5/11`
`=(6/11 + 5/11)+2/15`
`= 1 + 2/15`
`= 15/15 +2/15`
`= 17/15`
`-----`
`4/9 + 2/5 + 15/27`
`= (4/9 + 15/27 )+2/5`
`= 1+2/5`
`=5/5 +2/5`
`=7/5`
`-----`
`6/13 + 9/32 + 21/26`
`= (6/13 + 21/26)+9/32`
`= ( 12/26 + 21/26)+9/32`
`= 33/26 +9/32`
`=645/416`
![](https://rs.olm.vn/images/avt/0.png?1311)
7/15 + 4/15 = 11/15
13/5 - 2 = 13/5 - 10/5 = 3/5
4/7 x 5/8 = 20/56=5/14
8/3 : 8 = 8/3 x 1/8 = 8/24 = 1/3
![](https://rs.olm.vn/images/avt/0.png?1311)
y : 3/7 = 7/15
y = 7/15 x 3/7
y = 1/5
\(y:\dfrac{3}{7}=\dfrac{13}{15}-\dfrac{6}{15}\)
\(y:\dfrac{3}{7}=\dfrac{7}{15}\)
\(y=\dfrac{7}{15}\times\dfrac{3}{7}\)
\(y=\dfrac{1}{5}\)