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3x=234—> 243 chứ bạn
3x=243
Vì 35=243
Nên x=5
3x=4096
6x=216
Vì 63=216
Nên x=3
5.3x=405
3x=405:5
3x=81
Vì 34=81
Nên x=4
2x=4
Vì 22=4
Nên x=2
x5=32
Vì 25=32
Nên x=5
x4=81
Vì 34=81 và (-3)4=81
Nên x=3 hoặc x=-3
(x—2)5=243
(x—2)5=35
Nên x—2=3
x=3+2
x=5
(x—1)4=16
(x—1)4=24
Nên x—1 =2 hoặc x—1=-2
x=2+1 hoặc x=-2 +1
x=3 hoặc x=-1
(x+1)3=125
(x+1)3=53
Nên x+1=3
x=3-1
x=1
(x—2)3=64
(x—2)3=43
Nên x—2=4
x=4+2
x=6
(x—1)5=32
(x—1)5=25
==> x—1=5
x=5+1
x=6
\(3^x=243\Rightarrow3^x=3^5\Rightarrow x=5\)
câu thứ 2 mn chịu
\(6^x=216\Rightarrow6^x=6^3\Rightarrow x=3\)
\(5.3^x=405\\ 3^x=405:5\\ 3^x=81\\ \Rightarrow3^x=3^4\\ \Rightarrow x=4\)
\(2^x=4\\ \Rightarrow2^x=2^2\\ \Rightarrow x=2\)
\(x^5=32\\ \Rightarrow x^5=2^5\\ \Rightarrow x=2\)
câu 7 mn ko hỉu
\(x^4=81\\ x^4=\left(+-3\right)^4\\ x=+-3\)
câu 9 mn chịu
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a) 3^x.9^6=3^14 b,27^9.(3^x) = 3^31
=3^x.3^12=3^14 =>3^27.(3^x)^2=3^31
=> 3^x+12=3^14 => (3^x)^2=3^31.3^27
=> x=2 =>(3^x)^2=3^4=>2^x=4
=>x=2
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\(\left(x+1\right)^3=2^3.3+3\)
\(\Rightarrow\left(x+1\right)^3=24+3=27=3^3\)
\(\Rightarrow x+1=3\Rightarrow x=2\)
\(5+2.3^x+2=23\)
\(\Rightarrow7+2.3^x=23\)
\(\Rightarrow2.3^x=23-7=16\)
\(\Rightarrow3^x=8.\)
Mà số 3 lũy thừa mấy cũng không thể bằng 8 => x không thỏa mãn.
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125% : \(x\) + 234 = 7,75
125% : \(x\) = 7,75 - 234
125% : \(x\) = - 226,25
\(x\) = 125% : (- 226,25)
\(x\) = - \(\dfrac{1}{181}\)
125% : x + 234 = 7,75
\(\dfrac{5}{4}\) : x + 234 = 7,75
\(\dfrac{5}{4}\) : x = 7,75 - 234
\(\dfrac{5}{4}\) : x = -226,25
x = \(\dfrac{5}{4}\) : (-226,25)
x = \(\dfrac{1}{181}\)
tick cho mik
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a, \(5^{x-1}=100:2^2\)\(->5^{x-1}=25\\ ->5^{x-1}=5^2\)\(->x-1=2\\ x=2\)
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`@` `\text {Ans}`
`\downarrow`
`a)`
\(5\cdot x^3-5=0\)
`=> 5*x^3 = 0+5`
`=> 5*x^3 = 5`
`=> x^3 = 5 \div 5`
`=> x^3 = 1`
`=> x^3 = 1^3`
`=> x=1`
Vậy, `x=1.`
`b)`
\(( x+1)^2 = 16\)
`=> (x+1)^2 = (+-4)^2`
`=>`\(\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=4-1\\x=-4-1\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy, `x \in {3; -5}`
`c)`
\(( x+1)^3 = 27\)
`=> (x+1)^3 = 3^3`
`=> x+1=3`
`=> x=3-1`
`=> x=2`
Vậy, `x=2.`
`d)`
\(( x-1)^3 = 343\)
`=> (x-1)^3 = 7^3`
`=> x-1=7`
`=> x=7+1`
`=> x=8`
Vậy, `x=8.`
`e)`
\((2x - 1^3) = 125\) hay đề là `(2x-1)^3 = 125` vậy ạ?
Mình làm cả 2 TH nhé!
`(2x-1^3)=125`
`=> 2x-1=125`
`=> 2x=125+1`
`=> 2x=126`
`=> x=126 \div 2`
`=> x=63`
TH2:
`(2x-1)^3 = 125`
`=> (2x-1)^3 = 5^3`
`=> 2x-1=5`
`=> 2x=5+1`
`=> 2x=6`
`=> x=6 \div 2`
`=> x=3`
Vậy, `x=3.`
(a) \(5x^3-5=0\Leftrightarrow5x^3=5\Leftrightarrow x^3=1\Leftrightarrow x=1\)
(b) \(\left(x+1\right)^2=16\Rightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
(c) \(\left(x+1\right)^3=27\Leftrightarrow x+1=3\Leftrightarrow x=2\)
(d) \(\left(x-1\right)^3=343\Leftrightarrow x-1=7\Leftrightarrow x=8\)
(e) \(\left(2x-1\right)^3=125\Leftrightarrow2x-1=5\Leftrightarrow2x=6\Leftrightarrow x=3\)
\(\left(x-2\right)^5=3^5\) \(\left(x+1\right)^3=5^3\)
\(\Rightarrow x-2=3\) \(\Rightarrow x+1=5\)
\(x=3+2\) \(x=5-1\)
\(x=5\) \(x=4\)