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a/ \(x\left(x+7\right)=0\) \(\Rightarrow\left[\begin{matrix}x=0\\x+7=0\end{matrix}\right.\) \(\Rightarrow\left[\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
b/ \(\left(-x+5\right)\left(3-x\right)=0\) \(\Rightarrow\left[\begin{matrix}-x+5=0\\3-x=0\end{matrix}\right.\) \(\Rightarrow\left[\begin{matrix}x=5\\x=3\end{matrix}\right.\)
c/ \(\left|x-1\right|=3\) \(\Rightarrow\left[\begin{matrix}x-1=3\\1-x=3\end{matrix}\right.\) \(\Rightarrow\left[\begin{matrix}x=4\\x=-2\end{matrix}\right.\)
d/ \(-13\left|x\right|=-26\) \(\Rightarrow\left|x\right|=2\) \(\Rightarrow x=\pm2\)
e/ \(x.x-8=-2.\left(-13\right)-\left(-2\right)\)
\(\Rightarrow x^2=36\) \(\Rightarrow\left|x\right|=6\) \(\Rightarrow x=\pm6\)
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240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
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x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`(x+2)-2=0`
`=>x+2=0+2`
`=>x+2=2`
`=>x=2-2`
`=>x=0`
__
`(x+3)+1=7`
`=>x+3=7-1`
`=>x+3=6`
`=>x=6-3`
`=>x=3`
__
`(x+3)+4=12`
`=>x+3=12-4`
`=>x+3=8`
`=>x=8-3`
`=>x=5`
__
`(5x+4)-1=13`
`=>5x+4=13+1`
`=>5x+4=14`
`=>5x=14-4`
`=>5x=10`
`=>x=10:5`
`=>x=2`
__
`(4x-8)+3=12`
`=>4x-8=12-3`
`=>4x-8=9`
`=>4x=9+8`
`=>4x=17`
`=> x=17/4`
__
`3+(x-5)=14`
`=>x-5=14-3`
`=>x-5=11`
`=>x=11+5`
`=>x=16`
Tui mới lớp 1 à....tui ko bít:
/x-13/=5 suy ra x-13 = 5 hoặc -5 suy ra x=....hoặc.....
/-x+8/=/1-8/ suy ra /-x+8/=7 suy ra -x+8=7 hoặc -7 suy ra x=.....hoặc.....
/x+3/+/y-2/=0 suy ra /x+3/=/y-2/=0 suy ra x=....và y=......
THE END...
a) \(\left|x-13\right|=5\)
\(\Rightarrow\orbr{\begin{cases}x-13=5\\x-13=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=18\\x=8\end{cases}}}\)
\(\Rightarrow x\in\left\{8;18\right\}\)
b) (và) \(\left|x+8\right|+3=25\)
\(\left|x+8\right|=22\)
\(\Rightarrow\orbr{\begin{cases}x+8=22\\x+8=-22\end{cases}\Rightarrow\orbr{\begin{cases}x=14\\x=-30\end{cases}}}\)
\(\Rightarrow x\in\left\{-30;14\right\}\)
c) (và) \(\left|-x+8\right|=\left|1-8\right|\)
\(\left|-x+8\right|=7\)
\(\Rightarrow\orbr{\begin{cases}-x+8=7\\-x+8=-7\end{cases}\Rightarrow\orbr{\begin{cases}-x=-1\\-x=-15\end{cases}\Rightarrow}\orbr{\begin{cases}x=1\\x=15\end{cases}}}\)
\(\Rightarrow x\in\left\{1;15\right\}\)
d) (và) Ta có: \(\hept{\begin{cases}\left|x+3\right|\ge0\\\left|y-2\right|\ge0\end{cases}}\)
Dấu "=" xảy ra <=> \(\hept{\begin{cases}\left|x+3\right|=0\\\left|y-2\right|=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=-3\\y=2\end{cases}}}\)