![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(x+1)+(x+2)+(x+3)+...+(x+1024)=2056
<=> (x+x+x+...+x)+(1+2+3+...+1024)=2056
Số số hạng x là : (1024-1):1+1=1024 số
Đặt A = 1+2+3+..+1024
Tổng A là : (1024+1)x1024:2=524800
=> 1024x + 524800= 2056
<=> 1024x= 2056-524800
<=> 1024x=- 522744
x= \(-\frac{522744}{1024}\)
- Đề bài có sai sót gì không bạn ?
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
b) \(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
c) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
d) \(x^2=x^3\Rightarrow x^3-x^2=0\Rightarrow x^2\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
e) \(3^{x-1}=27\Rightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
f) \(3^{x+1}=9\Rightarrow3^{x+1}=3^2\Rightarrow x+1=2\Rightarrow x=1\)
g) \(6^{x+1}=36\Rightarrow6^{x+1}=6^2\Rightarrow x+1=2\Rightarrow x=1\)
h) \(3^{2x+1}=27\Rightarrow3^{2x+1}=3^3\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)
i) \(x^{50}=x\Rightarrow x^{50}-x=0\Rightarrow x\left(x^{49}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}=1=1^{49}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
4n = 4096
4n = 212
n = 12
5n = 15625
5n = 56
n = 6
6n+3 = 216
6n+3 = 23.33
6n+3 = 63
n + 3 = 3
![](https://rs.olm.vn/images/avt/0.png?1311)
a,
13[x-9] = 169
=> x - 9 = 169/13
=> x - 9 = 13
=> x = 13+9
=> x = 22
b,
Viết lại đề:
7x+3 = 343
<=> 7x+3 = 73
=> x + 3 = 3
=> x = 3-3
=> x = 0
c,
230 + [16 + [x-5]] = 315 . 23
=> 230 + [16 + x - 5] = 315 . 8
=> 230 + 16 + x - 5 = 2520
=> 230 + 16 + x = 2520 + 5 = 2525
=> x = 2525 - 230 - 16 = 2279
d,
13.x - 32.x = 20171 - 12018
=> 13x - 9x = 2017 - 1
=> 4x = 2016
=> x = 504
a) 13 ( x-9 )=169
=> x-9 =169 : 13 =13
=> x=13+9 =22
b)\(7^{x+3}=343\)
\(7^x.7^3=343\)
\(7^x=343:7^3\)
\(7^x=1\Rightarrow x=1\)
c)230 + 16 +x -5 =315.8
241 +x =2520
x=2520-241=2279
d) 13x -\(3^2.x\)=2017-1
x(13-9)=2016
x.4=2016
x=2016:4
x=504
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^{x+3}.2^{x+1}=1024\)
\(\Leftrightarrow2^x.2^3.2^x.2=1024\)
\(\Leftrightarrow2^{2x}.2^4=2^{10}\)
\(\Leftrightarrow2^{2x}=2^{10}:2^4\)
\(\Leftrightarrow2^{2x}=2^6\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
vậy x=3
chúc bn hok tốt
\(2^{x+3}.2^{x+1}=1024\)
\(\Leftrightarrow2^{x+3+x+1}=1024\)
\(\Leftrightarrow2^{2x+4}=2^{10}\)
\(\Rightarrow2x+4=10\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
HỌC TỐT NHA !
![](https://rs.olm.vn/images/avt/0.png?1311)
21 x 22 x 23 x ... x 2x = 1024
=> 21+2+3+...+x = 210
=> 1 + 2 + 3 + ... + x = 10
=> (1 + x).x:2 = 10
=> (1 + x).x = 10.2
=> (1 + x).x = 20
=> (1 + x).x = 5.4
=> x = 4
Vậy x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 2x.16 = 1024 => 2x = 1024:16 => 2x = 64 => 2x = 26 => x = 6
b, x17 = x
=> x17 - x = 0
=> x(x16-1)=0
=> x = 0 hoặc x16 - 1 = 0
=> x = 0 hoặc x16 = 1
=> x = 0 hoặc x = 1
c, (2x-2)3=64
=> (2x-2)3 = 43
=>2x-2=4
=>2x=6
=>X=3
d,(x-6)2 = (x-6)3
=> (x-6)2-(x-6)3=0
=> (x-6)2-[1-(x-6)] = 0
=> (x-6)2 = 0 hoặc 1 - (x-6) = 0
=> x - 6 = 0 hoặc x - 6 = 1
=> x = 6 hoặc x = 7
e, 3 + 2x-1 = 24-[42-(22-1)]
=> 3 + 2x-1 = 11
=> 2x-1 = 8
=> 2x-1 = 23
=>x-1=3
=>x=4
![](https://rs.olm.vn/images/avt/0.png?1311)
+) \(x^2=121\)
\(\Rightarrow\orbr{\begin{cases}x^2=11^2\\x^2=\left(-11\right)^2\end{cases}}\Rightarrow\orbr{\begin{cases}x=11\\x=-11\end{cases}}\)
Vậy x = 11 hoặc x = -11
+) \(2^{x+3}=1024\)
\(\Rightarrow2^{x+3}=2^{10}\)
\(\Rightarrow x+3=10\)
\(\Rightarrow x=10-3\)
\(\Rightarrow x=7\)
Vậy x = 7
+) \(5^{x+1}=625\)
\(\Rightarrow5^{x+1}=5^4\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)
Vậy x = 3
_Chúc bạn học tốt_
![](https://rs.olm.vn/images/avt/0.png?1311)
b: \(F=2\left(\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{240}\right)\)
\(=2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{15}-\dfrac{1}{16}\right)\)
\(=2\cdot\dfrac{7}{16}=\dfrac{7}{8}\)
c: \(3G=1+\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}\)
\(\Leftrightarrow2G=1-\dfrac{1}{243}=\dfrac{242}{243}\)
hay G=121/243
d: \(2H=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^9}\)
\(\Leftrightarrow H=1-\dfrac{1}{1024}\)
\(\left(x-1\right)\cdot\left(x-1\right)^2.\left(x-1\right)^3=1024\)
\(\Rightarrow\left(x-1\right)^1.\left(x-1\right)^2.\left(x-1\right)^3=1024\)
\(\Rightarrow\left(x-1\right)^{1+2+3}=1024\)
\(\Rightarrow\left(x-1\right)^6=1024\)
\(\Rightarrow x=\varnothing\)