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\(\frac{2010.2011-1005}{2010.2010+1005}\)
\(=\frac{2010.\left(2010+1\right)-2005}{2010.2010+1005}\)
\(=\frac{2010.2010+2010-1005}{2010.2010+1005}\)
\(=\frac{2010.2010+1005}{2010.2010+1005}\)
\(=1\)
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ko chép đề bài
A= (2012-1) . (2-1) +1
A= 2012
A= (2012+1) . 2012 :2
A= 2025078
k hộ cái
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Ta có: a= 2009 x 2010 = 2009 x (2010+1)=2009 x 2010 + 2009
b= 2010 x 2010= 2010 x (2009+1)=2010 x 2009 + 2010
=> a < b (Vì 2009 x 2010 + 2009 < 2010 x 2009 + 2010)
Vậy a < b
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\(1-\frac{1}{x+20}=\frac{1005}{2011}\)
\(\frac{1}{x+20}=1-\frac{1005}{2011}\)
\(\frac{1}{x+20}=\frac{1006}{2011}\)
=>1006.(x+20)=2011.1
=>1006x+20120=2011
1006x=2011-20120=-18109
x=\(\frac{-18109}{1006}\)
\(1-\frac{1}{\left(x+20\right)}=\frac{1005}{2011}\)
\(\Rightarrow\frac{1}{\left(x+20\right)}=1-\frac{1005}{2011}=\frac{1006}{2011}\)
\(\Rightarrow1:\left(x+20\right)=\frac{1006}{2011}\)
\(\Rightarrow x+20=\frac{2011}{1006}\)
\(\Rightarrow x=\frac{2011}{1006}-20=\frac{-18109}{1006}\)
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Ta có A=2010/2011+2011/2012+2012/2010
= (2010/2011+1/2011)+1+(2011/2012+1/2012)
=1+1+1=3
=> A=3
tui tic rùi ông tic lại tui
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