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C =[125.(73-75)]:(-25)2
=125.(-2):(-25).2
=-250:(-50)
=5
E=125.9.(-4).(-8).25.7
=125.(-8).25.(-4).7.9
=-1000.(-100).63
=6300000
C = ( 125 . 73 - 125 . 75 ) : ( -50)
C = 125 .( -2 ) : (-50)
C = -250 : -50
C = 50
G = ( -3 )2+( -5)3: l -5 l
G = 9 + ( -125) : 5
G = 9 + ( -25 )
G= ( -16 )
E = 125 .9.*( -4 ) . ( -8) .25.7
E = 25.5 .( -4 ) .9 .2. ( -4 ) .25 .7
E =( -100 ).10.( -100).63
E = 10000.630
E = 630000
**** mha
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
(2/3.5/7 + 2/3: 7/2). -1/3
=(10/21 + 2/3x2/7 ) . -1/3
=(10/21 + 4/21) . -1/3
=-10/63 - 4/63
=-14/63
(2/3.5/7+2/3:7/2)-1/3
=(2/3.5/7+2/3x2/7)-1/3
=[2/3.(5/7+2/7)]-1/3
=[2/3x1]-1/3
=2/3-1/3
=1/3
HT
a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)
43.25.16=(22)3.25.24=26.25.24=215
32.64.82=25.26.26=217
=> A=217:215=217-15=22=4
Đáp số: A=4
\(\frac{32.64.8^2}{4^3\cdot2^5\cdot16}=\frac{2^5.2^6.2^6}{2^6.2^5.2^3}\)
\(=\frac{2^{5+6+6}}{2^{6+5+3}}=\frac{2^{17}}{2^{14}}=2^{17-14}=2^3=8\)
Mình giải thích thêm nha
\(8^2=\left(2^3\right)^2=2^6\)
\(4^3=\left(2^2\right)^3=2^6\)