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\(=\dfrac{\left[\left(10.4+8.1\right)^2-6.5^2\right]:0.025}{576-336}+25+\dfrac{4}{3}-\dfrac{4}{3}\)
\(=\dfrac{3000}{240}+25=\dfrac{25}{2}+25=37.5\)
Ai bít giải chi tiết ra hk ạ????
Giúp e với !!!!!!Làm ơn làm phước, đúng e k cho mak TTTTTTTTT
a)
\(\begin{array}{l}\left( {0,25 - \frac{5}{6}} \right).1,6 + \frac{{ - 1}}{3}\\ =(\frac{25}{100}-\frac{5}{6}).\frac{16}{10}+\frac{-1}{3}\\= \left( {\frac{1}{4} - \frac{5}{6}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \left( {\frac{6}{{24}} - \frac{{20}}{{24}}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{24}}.\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 5}}{{15}}\\ = \frac{{ - 19}}{{15}}\end{array}\)
b)
\(\begin{array}{l}3 - 2.\left[ {0,5 + \left( {0,25 - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left[ {\frac{1}{2} + \left( {\frac{1}{4} - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left( {\frac{1}{2} + \frac{1}{{12}}} \right)\\ =3-2.(\frac{6}{12}+\frac{1}{12})\\= 3 - 2.\frac{7}{{12}}\\ = 3 - \frac{7}{6}\\=\frac{18}{6}-\frac{7}{6}\\ = \frac{{11}}{6}\end{array}\)
c) \(\left[3\frac{1}{6}-\left(0,06\cdot7\frac{1}{2}+6\frac{1}{4}\cdot0,24\right)\right]:\left(1\frac{2}{3}+2\frac{2}{3}\cdot1\frac{3}{4}\right)\)
\(=\left[\frac{19}{6}-\left(\frac{3}{50}\cdot\frac{15}{2}+\frac{25}{4}\cdot\frac{6}{25}\right)\right]:\left(\frac{5}{3}+\frac{8}{3}\cdot\frac{7}{4}\right)\)
\(=\left[\frac{19}{6}-\left(\frac{9}{20}+\frac{3}{2}\right)\right]:\left(\frac{5}{3}+\frac{14}{3}\right)\)
\(=\left(\frac{19}{6}-\frac{39}{20}\right):\frac{19}{3}=\frac{73}{60}:\frac{19}{3}=\frac{73}{60}\cdot\frac{3}{19}=\frac{73}{380}\)
Bài giải
\(c,\text{ }\left[3\frac{1}{6}-\left(0,06\cdot7\frac{1}{2}+6\frac{1}{4}\cdot0,24\right)\right]\text{ : }\left(1\frac{2}{3}+2\frac{2}{3}\cdot1\frac{3}{4}\right)\)
\(=\left[\frac{19}{6}-\left(\frac{3}{50}\cdot\frac{15}{2}+\frac{25}{4}\cdot\frac{6}{25}\right)\right]\text{ : }\left(\frac{5}{3}+\frac{8}{3}\cdot\frac{7}{4}\right)\)
\(=\left[\frac{19}{6}-\left(\frac{9}{20}+\frac{3}{2}\right)\right]\text{ : }\left(\frac{5}{3}+\frac{56}{12}\right)\)
\(=\left(\frac{19}{6}-\frac{39}{20}\right)\text{ : }\frac{19}{3}\)
\(=\left(\frac{190}{60}-\frac{117}{60}\right)\cdot\frac{3}{19}=\frac{73}{60}\cdot\frac{3}{19}=\frac{73}{380}\)
