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Ta có: \(\left(3\dfrac{3}{4}+\dfrac{4}{7}\cdot\dfrac{7}{16}\right):\dfrac{1}{2}\)
\(=\left(\dfrac{15}{4}+\dfrac{1}{4}\right)\cdot2\)
\(=4\cdot2=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\left(3\dfrac{3}{4}+\dfrac{4}{7}\cdot\dfrac{7}{16}\right):\dfrac{1}{2}\)
\(=\left(\dfrac{15}{4}+\dfrac{1}{4}\right)\cdot2\)
\(=4\cdot2=8\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(A=\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{2003}\right).\left(1-\dfrac{1}{2004}\right)\)
\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}...\dfrac{2002}{2003}.\dfrac{2003}{2004}\)
\(=\dfrac{1}{2004}\)
b) \(B=5\dfrac{9}{10}:\dfrac{3}{2}-\left(2\dfrac{1}{3}.4\dfrac{1}{2}-2.2\dfrac{1}{3}\right):\dfrac{7}{4}\)
\(=\dfrac{59}{10}:\dfrac{3}{2}-\left(\dfrac{7}{3}.\dfrac{9}{2}-2.\dfrac{7}{3}\right).\dfrac{4}{7}\)
\(=\dfrac{59}{15}-\left(\dfrac{21}{2}-\dfrac{14}{3}\right).\dfrac{4}{7}\)
\(=\dfrac{59}{15}-\dfrac{35}{6}.\dfrac{4}{7}\)
\(=\dfrac{59}{15}-\dfrac{10}{3}\)
\(=\dfrac{3}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
p) Thay x=−8 ta có:
(−55).(−25).[−(−8)]
=(−55).(−25).8
=11000
q)
(-1).(-2).(-3).(-4).(-5).(-x) với x=-10
Thay x=−10 ta có:
(-1).(-2).(-3).(-4).(-5).(-10)
= 1200
r)
12.(-3).(-7).x với x=-2
thay x=-2 ta có
12.(-3).(-7).(-2)
=(-36).(-7).(-2)
= 252.(-2)
=-504
![](https://rs.olm.vn/images/avt/0.png?1311)
p] [-55].[-25].[-8]
={[-25].[-8]}.[-55]
=200.[-55]
=-11000
chúc bạn học tốt
q(-1).(-2).(-3).(-4).(-5).(-10)
=[(-10).(-1)].[(-2).(-5)].[(-3).(-4)]
=10.10.12
=100.12
=1200
9.4^2-7.2^3=9.16-7.8=144-56=88