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b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)
a)67/63 x 15/3 + 15/31 x 11/21
Thiếu đề
b)15/31 x 34/63 - 11/21 x 15/31
=15/31 x ( 34/63 -11/21)
= 15/31 x 1/63= 5/651
b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)
b: =15/31(34/63-11/21)=15/31x1/63=5/651
a: =67/63⋅5+11/31⋅5/7=5(67/63+11/31⋅7)=10880/1953
\(11-12+13-14+15-16+17-18+19-20+21+22\)
\(=\left(11+13+15+17+19+21+22\right)-\left(12+14+16+18+20\right)\)
\(=\left(A+22\right)-B\)
số số hạng của tổng A là :
( 21 - 11 ) :2 + 1 = 6 ( số )
vậy tổng A là :
( 21 + 11 ) * 6 :2 = 96
số số hạng của tổng B là :
(20-12 ) :2 +1 = 5 ( số )
tổng B là :
( 20 + 12 ) * 5 :2 = 80
vậy \(\left(A+22\right)-B\)
\(=\left(96+22\right)-80\)
\(=118-80\)
\(=38\)
\(11-12+13-14+15-16+17-18+19-20+21+22\)
\(=\left(11-12\right)+\left(13-14\right)+\left(15-16\right)+\left(17-18\right)+\left(19-20\right)+21+22\)
\(=-1+-1+-1+-1+-1+21+22\)
\(=-5+21+22\)
\(=38.\)
20 + 21 + 30 + 31
= 20 + 20 + 1 + 30 + 30 + 1
= (20 + 20) + (1 + 1) + (30 + 30)
= 40 + 2 + 60
= (40 + 60) + 2
= 100 + 2
= 102
20 + 21 + 30 + 31
= (20 + 30) + (21 + 31)
= 50 + 52
= 102
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)
= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)
= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)
b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)
= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)
a: \(\dfrac{18}{31}+\dfrac{11}{31}+\dfrac{12}{31}=\dfrac{18+11+12}{31}=\dfrac{41}{31}\)
b: \(\dfrac{13}{21}+\dfrac{4}{21}+\dfrac{17}{21}=\dfrac{13+4+17}{21}=\dfrac{34}{21}\)
a) $\frac{18}{31} + \frac{11}{31} + \frac{12}{31} = \frac{18+11+12}{31} = \frac{41}{31} = 1\frac{10}{31}$
b) $\frac{13}{21} + \frac{4}{21} + \frac{17}{21} = \frac{13+4+17}{21} = \frac{34}{21} = 1\frac{13}{21}$