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\(\dfrac{2}{5}\) x y : \(\dfrac{7}{4}\) = \(\dfrac{7}{8}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{7}{8}\) x \(\dfrac{7}{4}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{49}{32}\)
y = \(\dfrac{49}{32}\) : \(\dfrac{2}{5}\)
y = \(\dfrac{245}{64}\)
2\(\dfrac{2}{5}\): y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}\): y x \(\dfrac{5}{4}\) = \(\dfrac{13}{5}\)
\(\dfrac{12}{5}\): y = \(\dfrac{13}{5}\): \(\dfrac{5}{4}\)
\(\dfrac{12}{5}\): y = \(\dfrac{52}{25}\)
y = \(\dfrac{12}{5}\): \(\dfrac{52}{25}\)
y = \(\dfrac{15}{13}\)
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` 242/363 + 1616/2121 = 2/7 xxy`
`2/7 xxy= 2/3 + 16/21`
`2/7 xxy= 14/21 +16/21`
`2/7 xxy= 30/21`
`y=10/7 : 2/7`
`y=10/7 xx 7/2`
`y=70/14`
`y=5`
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` (y + 1/4) + (y + 1/16) + (y + 1/16) =2`
`(y+y+y)+(1/4 + 1/16+1/16)=2`
`3y + (4/16 +1/16 +1/16)=2`
`3y + 6/16=2`
`3y=2-6/16`
`3y= 32/16-6/16`
`3y= 26/16`
`y=26/16 : 3`
`y=26/48`
`y=13/24`
\(a,\dfrac{242}{363}+\dfrac{1616}{2121}=\dfrac{2}{7}\times y\)
\(\dfrac{2}{7}\times y=\dfrac{2\times121}{3\times121}+\dfrac{16\times101}{21\times101}\)
\(\dfrac{2}{7}\times y=\dfrac{2}{3}+\dfrac{16}{21}\)
\(\dfrac{2}{7}\times y=\dfrac{14}{21}+\dfrac{16}{21}\)
\(\dfrac{2}{7}\times y=\dfrac{30}{21}\)
\(\dfrac{2}{7}\times y=\dfrac{10}{7}\)
\(y=\dfrac{10}{7}:\dfrac{2}{7}\)
\(y=\dfrac{10}{7}\times\dfrac{7}{2}\)
\(y=5\)
\(---\)
\(b,\left(y+\dfrac{1}{4}\right)+\left(y+\dfrac{1}{16}\right)+\left(y+\dfrac{1}{16}\right)=2\)
\(\left(y+y+y\right)+\left(\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{16}\right)=2\)
\(3\times y+\left(\dfrac{4}{16}+\dfrac{2}{16}\right)=2\)
\(3\times y+\dfrac{6}{16}=2\)
\(3\times y+\dfrac{3}{8}=2\)
\(3\times y=2-\dfrac{3}{8}\)
\(3\times y=\dfrac{16}{8}-\dfrac{3}{8}\)
\(3\times y=\dfrac{13}{8}\)
\(y=\dfrac{13}{8}:3\)
\(y=\dfrac{13}{8}\times\dfrac{1}{3}\)
\(y=\dfrac{13}{24}\)
#\(Toru\)
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\(y+y.\frac{1}{3}.\frac{9}{2}+y.\frac{7}{2}=25\)
\(y+y.6+y.\frac{7}{2}=25\)
\(y.\left(1+6+\frac{7}{2}\right)=25\)
\(y.\frac{21}{2}=25\)
\(y=25:\frac{21}{2}\)
\(y=25.\frac{2}{21}\)
\(y=\frac{50}{21}\)
\(y.5+y.3+y+y=50\)
\(y.\left(5+3+1+1\right)=50\)
\(y.10=50\)
\(y=5\)
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1/2-2y=9/20
=>2y=1/2-9/20=1/20
=>y=1/20:2=1/40
b,3/5:4/3:y=2+7/10=9/20:y=27/10
=>y=9/20:27/10=1/6
c,y+y*3/2-y*1/2=1/10
=>y(1+3/2-1/2)=1/10
=>2y=1/10
=>y=1/10:2=1/20
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7/4-y x 5/6 = 1/2+1/3
7/4-y x 5/6=5/6
y x 5/6=7/4-5/6
y x 5/6=11/12
y=11/12 : 5/6
y=11/10
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-y\times\frac{5}{6}=\frac{5}{6}\)
\(\frac{7}{4}-y=\frac{5}{6}\div\frac{5}{6}\)
\(\frac{7}{4}-y=1\)
\(y=1+\frac{7}{4}\)
\(y=\frac{11}{4}\)
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mình ko chép đề bài nha
a) \(\dfrac{16}{5}\): \(\dfrac{7}{3}\) : y =\(\dfrac{12}{7}\)
\(\dfrac{48}{35}\): y = \(\dfrac{12}{7}\)
y = \(\dfrac{48}{35}\): \(\dfrac{12}{7}\)
y = \(\dfrac{4}{5}\)
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Dấu \(.\)là dấu nhân
\(y+y.\frac{1}{4}:\frac{2}{7}+y:\frac{2}{9}=255\)
\(\Rightarrow y+y.\frac{1}{4}.\frac{7}{2}+y.\frac{9}{2}=255\)
\(\Rightarrow y+y.\frac{7}{8}+y.\frac{9}{2}=255\)
\(\Rightarrow y.\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)
\(\Rightarrow y.\left(\frac{8}{8}+\frac{7}{8}+\frac{36}{8}\right)=255\)
\(\Rightarrow y.\frac{51}{8}=255\)
\(\Rightarrow y=255:\frac{51}{8}\)
\(\Rightarrow y=255.\frac{8}{51}\)
\(\Rightarrow y=40\)
Vậy \(y=40\)
~ Ủng hộ nhé
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y : 7 + y x 2 = 1
y : 7 + y = 1 : 2 = 0.5
y + y = 0.5 x 7 = 3.5
y x 2 = 3.5
y = 1.75