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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(b,\Leftrightarrow\left(x-5\right)\left(x-4\right)\left(x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=4\\x=-4\end{matrix}\right.\\ c,\Leftrightarrow x-2015>0\Leftrightarrow x>2015\\ d,\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}3-x>0\\x+6>0\end{matrix}\right.\\\left\{{}\begin{matrix}3-x< 0\\x+6< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow-6< x< 3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì \(\left(8\times x-16\right)\times\left(x-5\right)=0\)
=> \(8\times x-16=0\) hoặc \(x-5=0\)
TH1:
\(8\times x-16=0\)
\(8\times x=16\)
\(x=16\div8\)
\(x=2\)
TH2:
\(x-5=0\)
\(x=5\)
Vậy \(x\in\left\{2;5\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1+|-2|+3+|-4|+5=15=> x+15=16=> x=1 thay vào ta được:
|1+1|+|1-2|+|1+3|+|1-4|+|1+5|=16
![](https://rs.olm.vn/images/avt/0.png?1311)
\(-\frac{2}{3}-\frac{5}{3}x=\frac{7}{16}x+\frac{5}{6}\)
\(-\frac{2}{3}-\frac{5}{6}=\frac{7}{16}x+\frac{5}{3}x\)
\(\Rightarrow-\frac{3}{2}=\frac{101}{48}x\)
\(\Rightarrow x=-\frac{3}{2}.\frac{48}{101}=-\frac{72}{101}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x}{-4}=\frac{-16}{x}\)
\(\Rightarrow x\cdot x=-16\cdot\left(-4\right)\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x^2=\left(\pm8\right)^2\)
\(\Rightarrow x=\pm8\)
a)\(\left(x-\frac{5}{8}\right).\frac{5}{18}=-\frac{15}{36}\)
\(\Rightarrow x-\frac{5}{8}=\frac{-15}{36}.\frac{18}{5}\)
\(\Rightarrow x-\frac{5}{8}=-\frac{3}{2}\)
\(\Rightarrow x=-\frac{12}{8}+\frac{5}{8}=-\frac{7}{8}\)
b)\(\frac{x}{-4}=\frac{-16}{x}\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x=\orbr{\begin{cases}8\\-8\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(8 - 16)(\(x\) - 5) = 0
\(x\) - 5 = 0
\(x\) = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
`(8x-16)(x-5)=0`
`=>8x-16=0` hoặc `x-5=0`
`=>8x=16` hoặc `x=5`
`=>x=16:8` hoặc `x=5`
`=>x=2` hoặc `x=5`
Vậy `x in{2;5}`
TH1: 8x-16=0 8x =0+16 8x =16 x =16:8 x =2 | TH2: x-5=0 x=0+5 x=5 |
(x+16)chia hết (x+5)
(x+5)+11 chia chết cho x+5
\(\Rightarrow\)11 chia hết cho x+5
\(\Rightarrow\)x+5 thuộc Ư(11)= 11
\(\Rightarrow\)x=6
(x+16):(x+5)
mà (x+5):(x+5)
=>(x+16)-(x+5):(x+5)
=>x+16-x+5:x+5
=>21:x+5
=>x+5={1;-1;3;-3;7;-7;21;-21}
=>x={-4;-6;-2;-8;2;-12;16;-26}
nếu đúng thì k nha