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(1-1/2)×(1-1/3)×(1-1/4)×(1-1/5)×1-1/6=1/2×2/3×3/4×4/5×5/6=1/6
![](https://rs.olm.vn/images/avt/0.png?1311)
C1:
`5/8 xx (1/5 +2)`
`=5/8 xx (1/5 +10/5)`
`=5/8 xx 11/5`
`=11/8`
C2:
`5/8 xx (1/5 +2)`
`=5/8 xx 1/5 + 5/8 xx 2`
`=1/8 + 10/8`
`=11/8`
![](https://rs.olm.vn/images/avt/0.png?1311)
mk ko viết đề nha:
a)=(1/2+1/2)+ (1/3+2/3)+(1/4 +3/4)+(1/5+4/5)
=(2/2 + 3/3) + (4/4 + 5/5)
=2/2 + 4/2
=6/4
À mik lm đc câu a thui nha!Nhưng k cho mik vs nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
a \(\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)
b \(\dfrac{22}{77}-\dfrac{14}{77}=\dfrac{8}{77}\)
c \(\dfrac{11}{13}\times\dfrac{26}{31}=11\times\dfrac{2}{31}=\dfrac{22}{31}\)
d \(\dfrac{1}{2}\times3\times\dfrac{2}{5}=\dfrac{3}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, x + 0 = 0
=> x = 0
Vậy x = 0
b, x(x - 1) = 0
=> x = 0 hoặc x - 1 = 0
=> x = 0 hoặc x = 1
Vậy x thuộc { 0 ; 1}
c, x + 5 = 0
x = 0 - 5
x = -5
Vậy x = -5
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(\left(x-\dfrac{2}{3}\right):\dfrac{1}{2}=\dfrac{5}{7}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{5}{7}\) x \(\dfrac{1}{2}\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{5}{14}\)
\(\Rightarrow x=\dfrac{5}{14}+\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{15}{42}+\dfrac{2}{42}\)
\(\Rightarrow x=\dfrac{17}{42}\)
b)
\(x\) x \(\dfrac{1}{2}=1-\dfrac{1}{3}\)
\(x\) x \(\dfrac{1}{2}=\dfrac{3}{3}-\dfrac{1}{3}\)
\(x\) x \(\dfrac{1}{2}=\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{2}{3}:\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{2}{3}\) x \(2=\dfrac{4}{3}\)
c)
\(\dfrac{26}{5}-x=\dfrac{9}{15}\) x \(\dfrac{25}{3}\)
\(\dfrac{26}{5}-x=5\)
\(\Rightarrow x=\dfrac{26}{5}-5\)
\(\Rightarrow x=\dfrac{26}{5}-\dfrac{25}{5}\)
\(\Rightarrow x=\dfrac{1}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= 51/20
----------------------------------
= 3/14
------------------------------------
= 4/7 - 2/7
= 2/7
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= 17/45
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= 2/3
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= 2 x 1/4
= 1/2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times\dfrac{4}{5}\times\dfrac{5}{6}\)
\(A=\dfrac{7}{2}\)
\(A=\dfrac{3}{2}\times\dfrac{4}{3}\times\dfrac{5}{4}\times\dfrac{6}{5}\times\dfrac{7}{6}\\ A=\dfrac{7}{2}\)
\(x-\dfrac{1}{5}=\dfrac{2}{5}+\dfrac{1}{3}=\dfrac{11}{15}\)
\(x=\dfrac{11}{15}+\dfrac{1}{5}=\dfrac{14}{15}\)
x-1/5=11/15
x =11/15+1/5
x =14/15 :v
HT