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\(3^x+3^{x+1}+3^{x+2}=117\)
\(\Leftrightarrow3^x+3^x.3^1+3^x.3^2=117\)
\(\Leftrightarrow3^x\left(1+3+3^2\right)=117\)
\(\Leftrightarrow3^x.13=117\)
\(\Leftrightarrow3^x=9=3^2\)
\(\Leftrightarrow x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x+3x+1+3x+2=117
=> 3x.(1+3+32)=117
=> 3x.(1+3+9)=117
=> 3x.13=117
=> 3x=117:13
=> 3x=9
=> 3x=32
=> x=2
3x+3x+1+3x+2=117
=> 3x.(1+3+32)=117
=> 3x.(1+3+9)=117
=> 3x.13=117
=> 3x=117:13
=> 3x=9
=> 3x=32
=> x= 2
tick nha
![](https://rs.olm.vn/images/avt/0.png?1311)
Gì mà cần xét trường hợp vậy
3^x+3.3^x+9.3^x=13.3^x=117=> 3^x=9=>x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^x+3^{x+1}+3^{x+2}=117\)
\(\Rightarrow3^x+3^x.3+3^x.9=117\)
\(\Rightarrow3^x.\left(1+3+9\right)=117\)
\(\Rightarrow3^x.13=117\)
\(\Rightarrow3^x=117:13\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(3^x+3^{x+1}+3^{x+2}=117\)
\(\Rightarrow3^x+3^x.3+3^x.9=117\)
\(\Rightarrow3^x.\left(1+3+9\right)=117\)
\(\Rightarrow3^x=117:13\)
\(\Rightarrow3^x=9\)
\(\Leftrightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^x+3^{x-1}+3^{x-2}=117\)
\(\Leftrightarrow3^x+\frac{3^x}{3}+\frac{3^x}{3^2}=117\)
\(\Leftrightarrow3^x.\left(1+\frac{1}{3}+\frac{1}{9}\right)=117\)
\(\Leftrightarrow3^x.\frac{13}{9}=117\)
\(\Leftrightarrow3^x=81\)
\(\Leftrightarrow3^x=3^4\)
\(\Leftrightarrow x=4\)
~Học tốt~
![](https://rs.olm.vn/images/avt/0.png?1311)
=> 3^x . (1+3+3^2) = 117
=> 3^x . 13 = 117
=> 3^x = 117 : 13 = 9
=> 3^x = 3^2
=> x = 2
Vậy x = 2
Tk mk nha
3x + 3x+1 +3x+2 = 117
=> 3x + 3x . 3 + 3x . 9 = 117
=> 3x ( 1 + 3 + 9) = 117
=> 3x . 13 = 117
=> 3x = 9
=> x = 2
3x + 3x+1 + 3x+2 = 117
=> 3x + 31 + 32 + 3x + 3x = 117
=> 3x . ( 31 + 32 + 1 ) = 117
=> 3x . 13 = 117
=> 3x = 117 : 13
=> 3x = 9
=> 3x = 32
=> x = 2
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