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a, 3 x - 2 3 = 2 . 32
3 x - 2 3 = 64
3 x - 2 3 = 4 3
3 x - 2 = 4 ⇔ x = 2
b, 5 x + 1 - 5 x = 500
5 x . 5 - 5 x = 500
5 x . ( 5 - 1 ) = 500
5 x . 4 = 500
5 x = 125 = 5 3
x = 3
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a, 42x - 6 = 1
=> 42 x = 7
=> x = 6
b, 5x + 5x + 1 +5x + 2 = 775
=> 15 x + 3 = 775
=> 15 x = 772
=> x = 772/ 15
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5\(^{x+1}\) - 5\(^x\) = 2.28 + 8
5\(^x\).(5 - 1) = 520
5\(^x\).4 = 520
5\(^x\) = 520 : 4
5\(^x\) = 130
Với \(x\) = 0 ⇒ 5\(^x\) = 50 = 1 < 130 (loại)
Với \(x\) > 0 ⇒ 5\(^x\) = \(\overline{...5}\) \(\ne\) 130 (loại)
Vậy \(x\) \(\in\) \(\varnothing\)
\(5^{x+1}-5^x=2.2^8+8\\ 5^x\left(5-1\right)=512+8\\ 5^x.4=520\\ 5^x=\dfrac{520}{4}=130\)
Em xem lại đề
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`@` `\text {Ans}`
`\downarrow`
`a,`
`x - 280 \div 35 = 554`
`=> x - 8 = 554`
`=> x = 554 + 8`
`=> x = 562`
Vậy, `x = 562`
`b,`
`x + (5 \div 3) = 500`
`=> x + 5/3 = 500`
`=> x = 500 - 5/3`
`=> x = 1495/3`
Vậy, `x = 1495/3`
`c,`
`390 \div (5x - 5) = 39`
`=> 5x - 5 = 390 \div 39`
`=> 5x - 5 = 10`
`=> 5x = 10 + 5`
`=> 5x = 15`
`=> x = 15 \div 5`
`=> x = 3`
Vậy, `x = 3`
`d,`
`34x - 14x = 200`
`=> (34 - 14)x = 200`
`=> 20x = 200`
`=> x = 200 \div 20`
`=> x = 10`
Vậy, `x = 10.`
`@` `\text {Kaizuu lv uuu}`
a) \(x-280:35=554\)
\(x-8=554\)
\(x=562\)
b) \(x+\left(5:3\right)=500\)
\(x+\dfrac{5}{3}=500\)
\(x=500-\dfrac{5}{3}=\dfrac{1500}{3}-\dfrac{5}{3}=\dfrac{1495}{3}\)
c) \(390:\left(5x-5\right)=39\)
\(5x-5=\dfrac{39}{390}=\dfrac{1}{10}\)
\(5x=5+\dfrac{1}{10}\)
\(5x=\dfrac{51}{10}\)
\(x=\dfrac{51}{10}.\dfrac{1}{5}=\dfrac{51}{50}\)
d) \(34x-14x=200\)
\(20x=200\)
\(x=200:20=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{5x}{1.6}+\dfrac{5x}{6.11}+\dfrac{5x}{11.16}+\dfrac{5x}{16.21}+\dfrac{5x}{21.26}+\dfrac{5x}{26.31}=1\)
\(=x\left(\dfrac{5}{1.6}+\dfrac{5}{6.11}+\dfrac{5}{11.16}+\dfrac{5}{16.21}+\dfrac{5}{21.26}+\dfrac{5}{26.31}\right)=1\)
\(=x\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{31}\right)=1\)
\(=x\left(1-\dfrac{1}{31}\right)=1\)
\(\Rightarrow x=1:\left(1-\dfrac{1}{31}\right)=\dfrac{31}{30}\)
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\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)
Tìm x ,y
xy + 5x +y =4
xy + 5x +y +5 = 9
( xy + y ) + ( 5x +5 ) =9
y.( x+1) + 5( x +1) =9
giải hộ mk tick
![](https://rs.olm.vn/images/avt/0.png?1311)
x(x+1) + 5x+5-9=0
x(x+1) + 5(x+1)-9(x+1)+9x=0
(x+1)(x+5-9)+9x=0
(x+1)(x-4)+4(x+1)-4+5x=0
(x+1)(x-4+4)-4+5x=0
(X+1)(x) -4 + 5x=0
sau 1 hồi phân tích . kết quả mình đéo làm dc mong bạn thông cảm :))
tích sai cc . mày nhìn bố m làm hẳn hoi này
(xy+y)+5x-4=0
y(x+1)+(5x+5)-9=0
y(x+1)+5(x+1)-3(x+1)-6+3x=0
(X+1)(y+2)-3(y+2)+3(x+y)
(y+2)(x-2)+3(x-2)+3(y+2)=0
(y+2)(x+1)+3x+3-5=0
(y+2)(x+1)+3(x+1)-5=0
(X+1)(y+2+3)
(X+1)(y+5)-(5+y)+y=0
(y+5)(x+1-1)+y=0
(y+5)(x)+y=0
kết quả vẫn éo làm dc :))))))))
5x+1 = 500 + 5x
<=> 5x+1 - 5x = 500
<=> 5x( 5 - 1 ) = 500
<=> 5x.4 = 500
<=> 5x = 125 = 53
<=> x = 3