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\(\dfrac{x-25-124}{2015}\) + \(\dfrac{x-124-2015}{25}\) + \(\dfrac{x-2015-25}{124}\) = 3
\(\dfrac{x-15-124}{2015}\) - 1 + \(\dfrac{x-124-2015}{25}\) - 1 + \(\dfrac{x-2015-25}{124}\) - 1 = 0
\(\dfrac{x-15-124-2015}{2015}\)+\(\dfrac{x-124-2015-25}{25}\)+\(\dfrac{x-2015-25-124}{124}\) = 0
\(\dfrac{x-\left(15+124+2015\right)}{2015}\)+\(\dfrac{x-\left(124+2015+25\right)}{25}\)+\(\dfrac{x-\left(2015+25+124\right)}{124}\) = 0
(\(x\) - 2164).(\(\dfrac{1}{2015}\)+\(\dfrac{1}{25}\)+\(\dfrac{1}{124}\)) = 0
\(x-2164\) = 0
\(x\) = 2164
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124 x 52 - 124 x 42
=124x(52-42)
=124x10
=1240
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\(\frac{x}{x+104}=\frac{1}{104}\)
=> \(104x=x+104\)
\(103x+x=104+x\)
\(103x=104\)(Trừ hai vế cho x)
\(x=104:103=\frac{104}{103}\)
Đ/S: 104/103
\(\frac{x}{x+104}=\frac{1}{104}\)
\(\Rightarrow104x=x+104\)
\(\Rightarrow x=\frac{104}{103}\)
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