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a: \(M=\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot x^3\cdot xy^2\cdot z^2=\dfrac{1}{2}x^4y^2z^2\)
Hệ số là 1/2
Biến là \(x^4;y^2;z^2\)
b: \(N=x^2y\left(4+5-3\right)=6x^2y=6\cdot2^2\cdot\left(-1\right)=-24\)
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\(=\frac{2x\left(x-2y\right)}{\left(x+2y\right)^2}:\frac{\left(2y-x\right)\left(2y+x\right)}{\left(x-2y\right)^2}:\frac{5xy\left(x-2y\right)}{\left(x+2y\right)^3}\)
Điều kiện: \(x\ne2y;x\ne-2y;x\ne0;y\ne0\)
\(=\frac{2x\left(x-2y\right)}{\left(x+2y\right)^2}:\frac{\left(2y+x\right)}{\left(x-2y\right)}:\frac{5xy\left(x-2y\right)}{\left(x+2y\right)^3}\)
\(=\frac{2x\left(x-2y\right)}{\left(x+2y\right)^2}\times\frac{x-2y}{x+2y}\times\frac{\left(x+2y\right)^3}{5xy\left(x-2y\right)}=\frac{2\left(x-2y\right)}{5y}\)
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a. \(2x^2y^3.\frac{1}{4}xy.\left(-3xy\right)=-\frac{3}{2}x^4y^5\text{ đa thức có bậc 4+5 = 9}\)
b. \(\left(-3xy^3\right)^3\left(-\frac{2}{3}x^4y\right)=-27x^3y^9\left(-\frac{2}{3}x^4y\right)=18x^7y^{10}\text{ có bậc 7+10 = 17}\)
c.. \(\frac{2}{3}xy^2-2xy+4x^2y+12+2xy^2-3xy-20-4x^2y=\frac{8}{3}xy^2-5xy-8\) có bậc 3
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BÀI 1:
A) THAY X =2 ; Y= 1/3 VÀO BIỂU THỨC
2. ( 2+ 2) + 1/3. ( 1/3 + 3) + 2^2 + 2. (1/3) ^2 + 4. 1/3
= 2.4 + 1/3 . 10/3+ 4+ 2. 1/9 + 4/3
= 8+ 10/9 + 4+ 2/9 + 4/3
= 44/3
B) THAY X= 2; Y= 1/3 VÀO BIỂU THỨC
( 2 + 1/3 ) . 2 + ( 2- 1/3 ) . 2
= 7/3 . 2 + 5/3 . 2
= 7/6 + 10/3
= 9/2
C) TA CÓ: ( X+ Y) X + ( X+Y ) X= 2. X.( X+Y)
THAY X= 2; Y= 1/3 VÀO BIỂU THỨC
2. 2.( 2+ 1/3)
= 4. 7/3
= 28/3
BÀI 2:
A) \(\left(x^2+6x+5\right)+\left(-3x+9\right)=x^2+6x+5-3x+9\)
\(=\left(6x-3x\right)+\left(5+9\right)+x^2\)
\(=3x+14+x^2\)
B) \(\left(2x^2+3x+7\right)-\left(-2x+5\right)=2x^2+3x+7+2x-5\)
\(=2x^2+\left(3x+2x\right)+\left(7-5\right)\)
\(=2x^2+5x+2\)
C) \(\left(6x^2y-6xy^2\right)+\left(7xy+4xy^2-x^2y\right)=6x^2y-6xy^2+7xy+4xy^2-x^2y\)
\(=\left(6x^2y-x^2y\right)+\left(4xy^2-6xy^2\right)+7xy\)
\(=5x^2y+\left(-2xy^2\right)+7xy\)
CHÚC BN HỌC TỐT!!!!
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A)\(5xyz.4x^2y^2.\left(-2x^3y\right)=\left(5.4.\left(-2\right)\right).\left(xx^2x^3\right).\left(yy^2y\right)=\left(-40\right)x^6y^4\)
- BẬC : 10
- HỆ SỐ: -40
B) \(-xy.\left(\frac{1}{2}x^3y^4\right).\left(\frac{-4}{7}x^2y^5\right)=\left(\frac{1}{2}.\frac{-4}{7}.\left(-1\right)\right).\left(xx^3x^2\right).\left(y^4y^5y\right)=\frac{2}{7}x^6y^{10}\)
- BẬC : 16
- HỆ SỐ: 2/7
C) \(\frac{5}{3}x^2y^4.\left(\frac{-6}{5}xy^3\right).\left(-xy\right)=\left(\frac{5}{3}.\frac{-6}{5}.\left(-1\right)\right).\left(x^2xx\right).\left(y^4y^3y\right)=2x^4y^8\)
- BẬC : 12
- HỆ SỐ : 2
D) \(\left(\frac{-1}{3}x^2y^5\right).\left(\frac{3}{4}xy\right).5x=\left(\frac{-1}{3}.\frac{3}{4}.5\right).\left(x^2xx\right).\left(y^5y\right)=\frac{-5}{4}x^4y^6\)
- BẬC : 10
- HỆ SỐ : -5 /4
CHÚC BN HỌC TỐT!!
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a: \(=\left(4xy^2+2xy^2\right)+\left(3x^2y-3x^2y\right)=6xy^2\)
b: \(=xy\left(\dfrac{1}{5}+\dfrac{1}{3}\right)+xy^2\left(\dfrac{4}{3}-\dfrac{2}{5}\right)=\dfrac{8}{15}xy+\dfrac{14}{15}xy^2\)
d: \(=\dfrac{-4}{9}\cdot\dfrac{3}{2}\cdot xy^2\cdot xy^3=-\dfrac{2}{3}x^2y^5\)
\(A=3x^2y-4xy+6x^2y+4xy=9x^2y\)
`@` `\text {Ans}`
`\downarrow`
`A = `\(3x^2y-4xy+6x^2y+4xy \)
`= (3x^2y + 6x^2y) + (-4xy + 4xy)`
`= 9x^2y + 0`
`= 9x^2y`
`@` `\text {Kaizuu lv uuu}`