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\(a,\\ Ta.có:\dfrac{16}{-19}< 0;\dfrac{15}{17}>0\\ \Rightarrow\dfrac{16}{-19}< \dfrac{15}{17}\\ b,\\ Ta.có:\dfrac{419}{-723}< 0;\dfrac{-697}{-313}>0\\ \Rightarrow\dfrac{419}{-723}< \dfrac{-697}{-313}\\ c,\dfrac{311}{256}>\dfrac{256}{256}=1;\dfrac{199}{293}< \dfrac{203}{203}=1\\ \Rightarrow\dfrac{311}{256}>\dfrac{199}{203}\)
a ) 16 − 19 < 0 < 15 17 b ) 419 − 723 < 0 < − 697 − 313
c ) 311 256 > 1 > 199 203 d ) 30 235 = 6 47 > 6 48 = 8 64 > 8 63 = 168 1323 e ) 19 60 < 20 60 = 30 90 < 31 90 f ) 15 23 > 14 23 = 70 115 > 70 117
a, ta có :
\(\hept{\begin{cases}\frac{6}{7}< 1\\\frac{11}{10}>1\end{cases}}\Rightarrow\frac{6}{7}< \frac{11}{10}\)
b, ta có :
\(\hept{\begin{cases}\frac{-5}{7}< 0\\\frac{2}{7}>0\end{cases}}\Rightarrow\frac{-5}{7}>\frac{2}{7}\)
c, ta có :
\(\hept{\begin{cases}\frac{419}{-723}< 0\\\frac{-697}{-313}>0\end{cases}}\Rightarrow\frac{419}{-723}< \frac{-679}{-313}\)
a,Ta có:
6/7< 1< 11/10
=> 6/7< 11/10
b,Ta có:
-5/17< 0< 2/7
=> -5/7< 2/7
a. \(\frac{6}{7}=\frac{60}{70};\frac{11}{10}=\frac{77}{70}\)
\(\frac{77}{70}>\frac{60}{70}\rightarrow\frac{11}{10}>\frac{6}{7}\)
b. \(\frac{-5}{17}< 0;\frac{2}{7}>0\rightarrow\frac{2}{7}>\frac{-5}{17}\)
c. \(\frac{419}{-723}< 0;\frac{-697}{-313}=\frac{697}{313}>0\Rightarrow\frac{-697}{-313}>\frac{419}{-723}\)
a)Ta có : 6/7 < 1
11/10 >1
Suy ra : 6/7 < 11/10
B) -5/17 < 0 và 2/7 >0
Suy ra -5/17 < 2/7
c) câu c mk ko bt xl bn nha
1. a, \(\frac{6}{7}\)=\(\frac{60}{70}\);\(\frac{11}{10}\)=\(\frac{77}{70}\)
vì \(\frac{60}{70}\)<\(\frac{77}{70}\)nên \(\frac{6}{7}\)<\(\frac{11}{10}\)
b, \(\frac{-5}{17}\)<0<\(\frac{2}{7}\)
c, \(\frac{419}{-723}\)<0<\(\frac{-697}{-313}\)
2.
Ta có :\(\frac{2}{6}\)=\(\frac{20}{60}\);\(\frac{5}{12}\)=\(\frac{25}{60}\);\(\frac{4}{15}\)=\(\frac{16}{60}\);\(\frac{8}{20}\)=\(\frac{24}{60}\);\(\frac{10}{30}\)=\(\frac{20}{60}\)
Vì \(\frac{16}{60}\)<\(\frac{20}{60}\)<\(\frac{24}{60}\)<\(\frac{25}{60}\)nên \(\frac{4}{15}\)<\(\frac{2}{6}\)=\(\frac{10}{30}\)<\(\frac{8}{20}\)<\(\frac{5}{12}\)
a) 16 − 19 < 0 < 15 17
b) 419 − 723 < 0 < − 697 − 313