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A = \(2^2.\left(1^2+2^2+3^2+...+10^2\right)=4.385=1540\)
B=\(3^2.\left(1^2+2^2+3^2+...+10^2\right)=385.9=3465\)
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S= 22+42+62+...+202
S=(2.1)^2+(2.2)^2+(2.3)^2+...+(2.10)^2
S=2^2.1^2+2^2.2^2+2^2.3^2+...+2^2.10^2
S=2^2(1^2+2^2+3^2+...+10^2)
S=4.385
S=1540
BN K CHO MIK NHA!
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\(S=\left(1.2\right)^2+\left(2.2\right)^2+\left(3.2\right)^2+...+\left(10.2\right)^2\)
\(S=1^2.2^2+2^2.2^2+3^2.2^2+...+10^2.2^2\)
\(S=2^2\left(1^2+2^2+3^2+...+10^2\right)\)
TA BIẾT
\(1^2+2^2+3^2+...+10^2=385\)( SÁCH GIÁO KHOA TOÁN LỚP 7 TRANG 25 )
NÊN
\(S=2^2.385=4.385=1540\)
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S=2^2+4^2+6^2+...+20^2
=(1.2)^2+(2.2)^2=(2.3)^2+....+(2.10)^2
=1^2.2^2+2^2.2^2+2^2.3^2+..+2^2.10^2
=2^2.(1^2+2^2+3^2+...+10^2)
=4.385=1540
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S = 22+42+62+...+202.
= ( 2 .1 )2 + ( 2 . 2 )2 + ( 2.3 )2+...+ ( 2.10 )2
= 22 . 12 + 22 . 22 + 22 . 32 + ... + 22 . 102
= 22 . ( 12 + 22 +32 + ... +102 )
= 4 . 385
= 1540
( Thiếu đề bài nhé )
S = 22 + 42 + 62 + ... + 202
= 22.(12 + 22 + 32 + ... + 102)
Đặt C = 12 + 22 + 32 + ... + 102
= 1.1 + 2.2 + 3.3 + ... + 10.10
= 1.(2 - 1) + 2.(3 - 1) + 3.(4 - 1) + ... + 10.(11 - 1)
= (1.2 + 2.3 + 3.4 + ... + 10.11) - (1 + 2 + 3 + ... + 10)
= 1.2 + 2.3 + 3.4 + .. + 10.11 - 55
Đặt D = 1.2 + 2.3 + 3.4 + .. + 10.11
=> 3D = 1.2.3 + 2.3.3 + 3.4.3 + ... + 10.11.3
=> 3D = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 10.11.(12 - 9)
=> 3D = 1.23 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 10.11.12 - 9.10.11
=> 3D = 10.11.12
=> 3D = 1320
=> D = 440
Thay D vào C ta có
C = 440 - 55 = 385
Thay C vào S
=> S = 385 x 4 = 1540
![](https://rs.olm.vn/images/avt/0.png?1311)
S=22+42+62+...+202
S=(2*1)2+(2*2)2+(2*3)2+...+(2*10)2
=22*12+22*22+...+22*102=22(12+22+32+...+102)=4*385=1540
Vậy S=1540
\(S=2^2+4^2+6^2+...+20^2\)
\(S=\left(2.1\right)^2+\left(2.2\right)^2+\left(2.3\right)^2+...+\left(2.10\right)^2\)
\(S=2^2.1^2+2^2.2^2+2^2.2^3+...+2^2.10^2\)
\(S=2^2\left(1^2+2^2+3^2+...+10^2\right)\)
\(S=2^2.385\)
\(S=4.385\)
\(S=1540\)