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a)\(x^2-6xy+9y^2-25z^2=\left[x^2-2.x.3y+\left(3y\right)^2\right]-\left(5z\right)^2\)
\(=\left(x-3y\right)^2-\left(5z\right)^2=\left(x-3y-5z\right)\left(x-3y+5z\right)\)
b)\(xyz+x^2yz-6yz=yz\left(x^2+x-6\right)=yz\left(x^2+3x-2x-6\right)\)
\(=yz\left[x\left(x+3\right)-2\left(x+3\right)\right]=yz\left(x-2\right)\left(x+3\right)\)
a.x2-6xy+9y2-25z2
= ( x2-6xy+9y2)-25z2
= [x2-2x3y+(3y)2]-25z2
= (x-3y)2-252
= (x-3y+25)(x-3y-25)
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\(5x^2-10xy+5y^2-20z^2=5\left(x^2-2xy+y^2-4z^2\right)=5.\left[\left(x-y\right)^2-\left(2z\right)^2\right]=5.\left(x-y-2z\right).\left(x-y+2z\right)\)
\(x^2-z^2+y^2-2xy=\left(x-y\right)^2-z^2=\left(x-y+z\right)\left(x-y-z\right)\)
\(x^2-2xy-4z^2+y^2=\left(x-y\right)^2-4z^2=\left(x-y-2z\right)\left(x-y+2z\right)\)
a) 5x2 - 10xy + 5y2
= 5 (x2 - 2xy + y2)
= 5 (x - y)2
b) x2 - z2 + y2 - 2xy
= (x2 + y2 - 2xy) - z2
= (x2 - 2xy + y2) - z2
= (x - y)2 - z2
= (x - y + z)(x - y - z)
c) x2 - 6xy - 25z2 : hinh nhu de bi sai , ban xem lai giup minh
d) x2 - 2xy - 4z2 + y2
= (x2 - 2xy + y2) - 4z2
= (x - y)2 - (2z)2
= (x - y + 2z)(x - y - 2z)
Chuc ban hoc tot
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mình k ghi lại đề nha bạn
\(=\left(x-y\right)^2-16z^2\\ =\left(x-y-4z\right)\left(x-y+4z\right)\)
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x²-6xy+9y²-36 =(x²-6xy+9y²)-36 =(x-3y)²-6² =(x-3y+6)(x-3y-6)
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= x^2 - 6xy + 9y^2 - 49
= x^2 - 6xy + ( 3y )^2 - 49
= (x - 3y)^2 - 7^2
= (x - 3y -7)( x-3y +7) tk cho mk nha
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a) \(x^3+8y^3+4x+8y\)
\(=x^3-2x^2y+4xy^2+4x+2x^2y-4xy^2+8y^3+8y\)
\(=\left(x^3-2x^2y+4xy^2+4x\right)+\left(2x^2y-4x^2y+8y^3+8y\right)\)
\(=x\left(x^2-2xy+4y^2+4\right)+2y\left(x^2-2xy+4y^2+4\right)\)
\(=\left(x^2-2xy+4y^2+4\right)\left(x+2y\right)\)
b) \(x^2+6xy+9y^2+5x+15y\)
\(=\left(x^2+6xy+9y^2\right)+\left(5x+15y\right)\)
\(=\left(x+3y\right)^2+5\left(x+3y\right)\)
\(=\left(x+3y\right)\left(x+3y+5\right)\)
c) \(25-x^2+2xy-y^2\)
\(=25-\left(x^2-2xy+y^2\right)\)
\(=25-\left(x-y\right)^2\)
\(=5^2-\left(x-y\right)^2\)
\(=\left(5+x-y\right)\left(5-x+y\right)\)
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a. \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)
b. \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)
a: \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)
b: \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)
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a) Ta có: \(x^2y^2-x^2+6xy-9y^2\)
\(=x^2y^2-\left(x^2-6xy+y^2\right)\)
\(=\left(xy\right)^2-\left(x-3y\right)^2\)
\(=\left(xy-x+3y\right)\left(xy+x-3y\right)\)
b) Ta có: \(9-x^2+2xy-y^2\)
\(=9-\left(x^2-2xy+y^2\right)\)
\(=9-\left(x-y\right)^2\)
\(=\left(9-x+y\right)\left(9+x-y\right)\)
= ( x - 3y )^2 - (5z)^2
= ( x - 3y - 5z ) ( x - 3y + 5z )
x2 - 6xy - 25z2 + 9y2
= (x - 3y)2 - (5z)2
= (x - 3y - 5z) . (x - 3y + 5z)
# Học tốt #