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\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\\ \left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\\ \left(x+\frac{1}{5}\right)^2=\frac{9}{25}\\ \left|\left(x+\frac{1}{5}\right)\right|=\frac{3}{5}\)
TH1: \(x=\frac{3}{5}-\frac{1}{5}\\ x=\frac{2}{5}\)
TH2: \(\left|\left(x+\frac{1}{5}\right)\right|=-\frac{3}{5}\\ x=-\frac{3}{5}-\frac{1}{5}\\ x=-\frac{4}{5}\)
\(a,\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{2}{5}\)
\(b,-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Rightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}+\frac{24}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)
\(\Rightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Rightarrow3x-\frac{7}{9}=-\frac{2}{3}\)
\(\Rightarrow3x=-\frac{2}{3}+\frac{7}{9}\)
\(\Rightarrow3x=\frac{1}{9}\)
\(\Rightarrow x=\frac{1}{27}\)
\(c,\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\)
a) 25 : x = x
25 = x^2
x^2 = ( +-5 )^2
b) 3358 : 23 = 2x - 6
146 = 2x - 6
2x = 152
x = 76
c) ( 2x + 1 )^3 = 27 = 3^3
=> 2x + 1 = 3
=> 2x = 2
=> x = 1
d) ( x - 2 )^3 = ( x - 2 )^2
( x - 2 )^2 . ( x - 2 ) - ( x -2 )^2 = 0
( x - 2 )^2 . [ ( x - 2 ) - 1 ] = 0
+) x - 2 = 0
=> x = 2
+) x - 2 - 1 = 0
x - 3 = 0
x = 3
\(25\div x=x\Rightarrow x.x=25\Rightarrow x^2=25\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)
\(3358\div23=2x-6\)
\(\Rightarrow2x-6=146\)
\(\Rightarrow2x=152\)
\(\Rightarrow x=\frac{152}{2}=76\)
\(\left(2x+1\right)^3=27\)
Mà \(3^3=27\)
Nên \(\left(2x+1\right)^3=3^3\)
\(\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)
\(\left(x-2\right)^3=\left(x-2\right)^2\)
\(\Rightarrow\left(x-2\right)^3-\left(x-2\right)^2=0\)
\(\Rightarrow\left(x-2\right)^2.\left(x-2-1\right)=0\)
\(\Rightarrow\left(x-2\right)^2.\left(x-3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=3\end{cases}}}\)
Vậy......................
a) 8^2x+1 = 2^27 : 2^12 = 2^5
2^6x.3 = 2^5
Suy ra : 6x . 3 = 5
6x = 5:3=5/3
x = 5/3 : 6 = 5/18
\(\left(2x-1\right)^3=27\)
\(\left(2x-1\right)^3=3^3\)
\(\Rightarrow2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
Chúc bn hok tốt
\(\left(2x-1\right)^3=27\)
\(\left(2x-1\right)^3=3^3\)
\(2x-1=3\)
\(2x=4\)
\(x=2\)
vậy x=3
`(4^{-2}:(1/3)^2xx1/2)/((-1/6)^2)`
`=((1/16:1/9)xx1/2)/(1/36)`
`=36xx1/2xx(1/16xx9)`
`=18xx9/16`
`=81/8`
Lời giải:
a.
$(25-2x)^3:5-3^2=4^2$
$(25-2x)^3:5=4^2+3^2=25$
$(25-2x)^3=25.5=5^3$
$\Rightarrow 25-2x=5$
$\Rightarrow 2x=20$
$\Rightarrow x=10$
b.
$2.3^x=10.3^{12}+8.27^4=10.3^{12}+8.3^{12}=18.3^{12}=2.3^{14}$
$\Rightarrow 3^x=3^{14}$
$\Rightarrow x=14$
\(\left(2x-1\right)^3=27\)
\(\Rightarrow\left(2x-1\right)^3=3^3\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=3+1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=\dfrac{4}{2}\)
\(\Rightarrow x=2\)
(2x-1)^3 = 27 = 3^3
=> 2x-1=3
=> x=2