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b: \(=8+2\cdot3-7\cdot1.3+3\cdot\dfrac{5}{4}=8.65\)
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1.39:
\(215=2\cdot10^2+1\cdot10^2+5\cdot10^0\)
\(902=9\cdot10^2+0\cdot10^1+2\cdot10^0\)
\(2020=2\cdot10^3+0\cdot10^2+2\cdot10^1+0\cdot10^0\)
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Bài 3:
a: Ta có: \(\dfrac{3x-1}{x-2}=\dfrac{-1}{3.2}\)
\(\Leftrightarrow9.6x-3.2=-x+2\)
\(\Leftrightarrow10.6x=5.2\)
hay \(x=\dfrac{26}{53}\)
b: Ta có: \(\dfrac{0.6}{2x-1}=\dfrac{2x-1}{2.4}\)
\(\Leftrightarrow\left(2x-1\right)^2=1.44\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=1.2\\2x-1=-1.2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=3.2\\2x=-0.2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.6\\x=-0.1\end{matrix}\right.\)
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5:
f(x)=0
=>x=1 hoặc x=-2
g(1)=0 và g(-2)=0
=>1+a+b+2=0 và -8+4a-2b+2=0
=>a=0 và b=-3