Question

[Ngọc Thảo]

Giúp với ạ , ai đang onl làm giúp luôn đi ah , mình cần gấp

Answer 1

[Hoàng Như Quỳnh]

\(1:a,x^4+2x^3+x^2\)

\(x^2\left(x^2+2x+1\right)\)

\(x^2\left(x+1\right)^2\)

\(\left(x^2+x\right)^2\)

\(b,25-x^2+4xy-4y^2\)

\(5^2-\left(x-2y\right)^2\)

\(\left(5-x+2y\right)\left(5+x-2y\right)\)

\(c,y^2-6y-9\)

\(\left(y-3\right)^2-18\)

\(\left(y-3\right)^2-\sqrt{18}^2=\left(y-3-3\sqrt{2}\right)\left(y-3+3\sqrt{2}\right)\)

\(d,x^2-2x-3\)

\(x^2-2x+1-4\)

\(\left(x-1\right)^2-2^2=\left(x-1-2\right)\left(x-1+2\right)\)

\(\left(x-3\right)\left(x+1\right)\)

\(e,9-x^2+2xy-y^2\)

\(9-\left(x^2-2xy+y^2\right)=9-\left(x-y\right)^2\)

\(\left(3-x+y\right)\left(3+x-y\right)\)

\(f,x^2-xz+y^2-yz+2xy\)

\(\left(x+y\right)^2-xz-yz\)

\(\left(x+y\right)^2-z\left(x+y\right)\)

\(\left(x+y\right)\left(x+y-z\right)\)

\(g,4x^2+4x-3\)

\(4x^2+4x+1-4\)

\(\left(x+1\right)^2-2^2=\left(x+1-2\right)\left(x+1+2\right)\)

\(\left(x-1\right)\left(x+3\right)\)

\(h,x^2-x-12\)

\(x^2-x+\frac{1}{2}-\frac{25}{2}\)

\(\left(x-\frac{1}{2}\right)^2-\left(\frac{5}{\sqrt{2}}\right)^2\)

\(\left(x-\frac{1}{2}-\frac{5}{\sqrt{2}}\right)\left(x-\frac{1}{2}+\frac{5}{\sqrt{2}}\right)\)

\(\left(x-\frac{1+5\sqrt{2}}{2}\right)\left(x-\frac{1-5\sqrt{2}}{2}\right)\)

\(i,4x^4+4x^2y^2-8y^4\)

\(\left(2x^2\right)^2+4x^2y^2+\left(y^2\right)^2-\left(3y^2\right)^2\)

\(\left(2x^2+y^2\right)^2-\left(3y^2\right)^2\)

\(\left(2x^2+y^2-3y^2\right)\left(2x^2+y^2+3y^2\right)=\left(2x^2-2y^2\right)\left(2x^2+4y^2\right)\)

\(k,x^4+4y^4\)

\(\left(x^2\right)^2+4x^2y^2+\left(2y^2\right)^2-4x^2y^2\)

\(\left(x^2+2y^2\right)^2-\left(2xy\right)^2\)

\(\left(x^2+2y^2-2xy\right)\left(x^2+2y^2+2xy\right)\)

\(l,ab^2+b^3\)

\(b^2\left(a+b\right)\)

\(m,a^3-a\)

\(a\left(a^2-1\right)\)

\(a\left(a-1\right)\left(a+1\right)\)

\(n,ab^2c^3+64ab^2\)

\(ab^2\left(c^3+64\right)\)

\(ab^2\left(c^3+4^3\right)\)

\(ab^2\left(c+4\right)\left(c^2+4c+16\right)\)