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a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(-2,5\times\left(x+\dfrac{1}{5}\right)=\dfrac{7}{5}\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}:\left(-2,5\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}\times\left(-\dfrac{2}{5}\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=-\dfrac{14}{25}\)
\(\Leftrightarrow x=-\dfrac{19}{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=(-1+2)-(3+4)-(5+6)-........-(2017+2018)
=1-7-11-........-4035
=-1009
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x - 1/2 = 3/5
x = 3/5 + 1/2
x = 11/10
b) x - 1/2 = -2/3
x = -2/3 + 1/2
x = -1/6
c) 2/5 - x = 0,25
x = 2/5 - 0,25
x = 2/5 - 1/4
x = 3/20
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^3\times20-5^3\times17-17\)
\(=5^3\left(20-17\right)-17\)
\(=5^3\times3-17\)
\(=125\times3-17\)
\(=358\)
20% .x+2/5=1,2 -8/5
20%. x +2/5=-2/5
20%.x =-2/5+2/5
20%.x=0
x=0/20%
x=0
Vì mik ko vt đc dấu phần trằm nên copy phần trăm trên gg mới ra mực xanh , thông cảm nha
\(1,2-20\%\cdot x+\dfrac{2}{5}=1\dfrac{3}{5}\)
=>\(1,2+0,4-0,2\cdot x=1,6\)
=>1,6-0,2x=1,6
=>0,2x=0
=>x=0