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\(\sqrt{5-x}-x=1\left(đk:5\ge x\ge-1\right)\)
\(\Leftrightarrow\sqrt{5-x}=x+1\)
\(\Leftrightarrow5-x=x^2+2x+1\)
\(\Leftrightarrow x^2+3x-4=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\left(tm\right)\\x=-4\left(ktm\right)\end{matrix}\right.\)
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\(b,\text{PT hoành độ giao điểm: }-2x=3x+3\\ \Leftrightarrow x=-\dfrac{3}{5}\Leftrightarrow y=\dfrac{6}{5}\\ \Leftrightarrow A\left(-\dfrac{3}{5};\dfrac{6}{5}\right)\)
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\(A=\sqrt{2a\left(b+1\right)}+\sqrt{2b\left(c+1\right)}+\sqrt{2c\left(a+1\right)}\)
\(A=\dfrac{1}{\sqrt{2}}\sqrt{4a\left(b+1\right)}+\dfrac{1}{\sqrt{2}}\sqrt{4b\left(c+1\right)}+\dfrac{1}{\sqrt{2}}\sqrt{4c\left(a+1\right)}\)
\(A\le\dfrac{1}{2\sqrt{2}}\left(4a+b+1\right)+\dfrac{1}{2\sqrt{2}}\left(4b+c+1\right)+\dfrac{1}{2\sqrt{2}}\left(4c+a+1\right)\)
\(A\le\dfrac{1}{2\sqrt{2}}\left[5\left(a+b+c\right)+3\right]=2\sqrt{2}\)
\(A_{max}=2\sqrt{2}\) khi \(a=b=c=\dfrac{1}{3}\)
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\(A=\frac{2\sqrt{x}+1+2\sqrt{x}-1-5+\sqrt{x}}{x-1}\)
\(A=\frac{5\sqrt{x}-5}{x-1}\)
\(A=\frac{5\left(\sqrt{x}-1\right)}{x-1}\)
\(A=\frac{5}{\sqrt{x}+1}\)