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AT
19 tháng 2 2017
a/ \(\frac{2}{3}+\frac{4}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{82}{105}< \frac{x}{105}< \frac{92}{105}\)
\(\Rightarrow82< x< 92\)
\(\Rightarrow x=\left\{83;84;85;86;87;88;89;90;91\right\}\)
b/ \(-\frac{7}{15}+\frac{8}{60}+\frac{24}{90}\le\frac{x}{15}\le\frac{3}{5}+\frac{8}{30}+-\frac{4}{10}\)
\(\Rightarrow-\frac{1}{15}\le\frac{x}{15}\le\frac{7}{15}\)
\(\Rightarrow-1\le x\le7\)
\(\Rightarrow x=\left\{-1;0;1;2;3;4;5;6;7\right\}\)
NN
\(\left(4\frac{5}{37}-3\frac{4}{5}+8\frac{15}{29}\right)-\left(3\frac{5}{37}-6\frac{14}{29}\right)\)
0
LT
\(\left(4\frac{5}{37}-3\frac{4}{5}+8\frac{15}{29}\right)-\left(3\frac{5}{37}-6\frac{14}{29}\right)\)
0
11 tháng 4 2019
\(1,-\frac{3}{29}+\frac{-7}{29}\le\frac{x}{29}\le-\frac{3}{29}-\frac{5}{29}\)
\(\Rightarrow-\frac{10}{29}\le\frac{x}{29}\le-\frac{8}{29}\Rightarrow-10\le x\le-8\)
\(\Rightarrow x=\left\{-8;-9;-10\right\}\)
\(S=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+...+\frac{1}{2^{99}}+\frac{1}{2^{100}}\)
\(\Rightarrow2S=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{99}}\)
\(S=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+...+\frac{1}{2^{99}}+\frac{1}{2^{100}}\)
\(\Rightarrow2S-S=S=1-\frac{1}{2^{100}}\)
11 tháng 4 2017
\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}......\frac{3599}{60^2}=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}......\frac{59.61}{60.60}=\frac{\left(1.2.3.4.....59\right).\left(3.4.5......60.61\right)}{\left(2.3.4......59.60\right).\left(2.3.4.5......60\right)}=\frac{1.61}{60.2}=\frac{61}{120}\)
\(\frac{3}{4}\)- \(\frac{2}{15}\). X =\(\frac{29}{60}\)
\(\frac{2}{15}\). X = \(\frac{29}{60}\)- \(\frac{45}{60}\)= \(\frac{-4}{15}\)
X = \(\frac{-4}{15}\). \(\frac{15}{2}\)
X = \(-2\)
Nhớ k cho mk nha
\(\frac{3}{4}\)- \(\frac{2}{15}.x=\frac{29}{60}\)
\(\frac{2}{15}.x=\frac{29}{60}+\frac{3}{4}\)
\(\frac{2}{15}.x=\frac{30}{37}\)
\(x=\frac{30}{37}:\frac{2}{15}\)
\(x=\frac{225}{37}\)
- đúng thì k giùm cái hen!!!!!!!!!