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1 tháng 5 2018
\(\frac{10}{3}\) . x \(+\)\(\frac{67}{4}\) \(=\)-13,25
\(\frac{10}{3}\) . x \(+\)\(\frac{67}{4}\) \(=\)\(\frac{-53}{4}\)
\(\frac{10}{3}\) . x \(=\)\(\frac{-53}{4}\)\(-\)\(\frac{67}{4}\)
\(\frac{10}{3}\) . x \(=\)\(-\)30
x \(=\)\(-\)30 \(\div\)\(\frac{10}{3}\)
x \(=\)\(-\)9
BT
24 tháng 3 2018
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
<=> \(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)=> \(\frac{10}{3}x=-\frac{120}{4}=-30\)
<=> X=(-3)*3 => X=-9
Đáp số: x=-9
TE
2
S
5 tháng 2 2017
\(3\frac{1}{3}.x+16\frac{3}{4}=-13,25\)
\(\frac{10}{3}x+16,75=-13,25\)
\(\frac{10}{3}x=-13,25-16,75\)
\(\frac{10}{3}x=-30\)
\(x=-9\)
Vậy \(x=-9\)
1 tháng 8 2020
a) Ta có: \(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)
\(\Leftrightarrow x\cdot\frac{2}{3}=\frac{1}{10}+\frac{1}{2}=\frac{6}{10}\)
hay \(x=\frac{6}{10}:\frac{2}{3}=\frac{6}{10}\cdot\frac{3}{2}=\frac{18}{20}=\frac{9}{10}\)
Vậy: \(x=\frac{9}{10}\)
b) Ta có: \(5\frac{4}{7}:x=13\)
\(\Leftrightarrow\frac{39}{7}:x=13\)
\(\Leftrightarrow x=\frac{39}{7}:13=\frac{39}{7}\cdot\frac{1}{13}=\frac{3}{7}\)
Vậy: \(x=\frac{3}{7}\)
c) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\Leftrightarrow\frac{14}{5}x-50=51\cdot\frac{2}{3}=34\)
\(\Leftrightarrow x\cdot\frac{14}{5}=84\)
\(\Leftrightarrow x=84:\frac{14}{5}=84\cdot\frac{5}{14}=\frac{420}{14}=30\)
Vậy: x=30
d) Ta có: \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
\(\Leftrightarrow\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}=\frac{-1}{15}\)
hay \(x=\frac{1}{3}:\frac{-1}{15}=\frac{1}{3}\cdot\left(-15\right)=\frac{-15}{3}=-5\)
Vậy: x=-5
e) Ta có: \(8\frac{2}{3}:x-10=-8\)
\(\Leftrightarrow\frac{26}{3}:x=2\)
hay \(x=\frac{26}{3}:2=\frac{26}{3}\cdot\frac{1}{2}=\frac{26}{6}=\frac{13}{3}\)
Vậy: \(x=\frac{13}{3}\)
g) Ta có: \(x+30\%=-1.3\)
\(\Leftrightarrow x+\frac{3}{10}=\frac{-13}{10}\)
hay \(x=\frac{-13}{10}-\frac{3}{10}=\frac{-16}{10}=\frac{-8}{5}\)
Vậy: \(x=\frac{-8}{5}\)
i) Ta có: \(3\frac{1}{3}x+16\frac{3}{4}=-13.25\)
\(\Leftrightarrow x\cdot\frac{10}{3}+\frac{67}{4}=-\frac{53}{4}\)
\(\Leftrightarrow x\cdot\frac{10}{3}=\frac{-53}{4}-\frac{67}{4}=-30\)
\(\Leftrightarrow x=-30:\frac{10}{3}=-30\cdot\frac{3}{10}=\frac{-90}{10}=-9\)
Vậy: x=-9
k) Ta có: \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\Leftrightarrow x\cdot\frac{14}{5}-50=51\cdot\frac{2}{3}=34\)
\(\Leftrightarrow x\cdot\frac{14}{5}=34+50=84\)
hay \(x=84:\frac{14}{5}=84\cdot\frac{5}{14}=30\)
Vậy: x=30
m) Ta có: \(\left|2x-1\right|=\left(-4\right)^2\)
\(\Leftrightarrow\left|2x-1\right|=16\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=16\\2x-1=-16\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=17\\2x=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{17}{2}\\x=\frac{-15}{2}\end{matrix}\right.\)
Vậy: \(x\in\left\{\frac{17}{2};\frac{-15}{2}\right\}\)
TC
2
22 tháng 4 2017
1) a) \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}\)
\(=\left(-0,75+\frac{1}{2}\right)\cdot\frac{3}{4}\)
\(=\left(-0,75+0,5\right)\cdot0,75\)
\(=-0,25\cdot0,75\)
\(=-0,1875\)
Vậy: \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}=-0,1875\)
b) \(\frac{7}{5}\cdot\frac{7}{4}-\frac{32}{5}\)
\(=\frac{49}{20}-\frac{32}{5}\)
\(=\frac{49}{20}-\frac{128}{20}\)
\(=-\frac{79}{20}=-3\frac{19}{20}\)
Vậy: \(\frac{7}{5}\cdot\frac{7}{4}-\frac{32}{5}=-3\frac{19}{20}\)
2) \(\frac{10}{3}\cdot x+\frac{67}{4}=-13,25\)
<=> \(\frac{10}{3}\cdot x+\frac{67}{4}=-\frac{53}{4}\)
<=> \(\frac{10}{3}\cdot x=-\left(\frac{53}{4}+\frac{67}{4}\right)\)
<=> \(\frac{10}{3}\cdot x=-30\)
<=> \(x=-30:\frac{10}{3}\)
<=> \(x=-30\cdot\frac{3}{10}\)
<=> \(x=-9\)
Vậy: \(x=-9\)
F
1
KN
12 tháng 1 2019
\(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
\(\Leftrightarrow\frac{3\times3+1}{3}x+\frac{16\times4+3}{4}=-13,25\)
\(\Leftrightarrow\frac{9+1}{3}x+\frac{64+3}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+\frac{67}{4}=-13,25\)
\(\Leftrightarrow\frac{10}{3}x+16,75=-13,25\)
\(\Leftrightarrow\frac{10}{3}x=-13,25-16,75\)
\(\Leftrightarrow\frac{10}{3}x=-30\)
\(\Leftrightarrow x=-30\div\frac{10}{3}\)
\(\Leftrightarrow x=\frac{-30}{1}\times\frac{3}{10}\)
\(\Leftrightarrow x=\frac{-90}{10}\)
\(\Leftrightarrow x=-9\)
10/3 x+67/4=-13,25
10/3x=-13,25-67/4
10/3x=-30
x=-30:10/3
x=-9
\(\frac{10}{3}x+\frac{67}{4}=-13.25\)
\(\frac{10}{3}x+\frac{67}{4}=-\frac{53}{4}\)
\(\frac{10}{3}x=-\frac{53}{4}-\frac{67}{4}\)
\(\frac{10}{3}x=-30\)
\(x=\left(-30\right):\frac{10}{3}\)
\(x=-9\)
Vậy x = -9