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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
P(1) = 1 + 2m + m^2
Q(-1) = 1 - (2m + 1) + m^2
= m^2 - 2m
P(1) = Q(-1)
=> m^2 + 2m + 1 = m^2 - 2m
=> 4m = -1
=> m = -1/4
Ta có :
\(P\left(1\right)=Q\left(-1\right)\)
\(\Rightarrow\)\(1^2+2m.1+m^2=\left(-1\right)^2.\left(2m+1\right).\left(-1\right)+m^2\)
\(\Leftrightarrow\)\(1+2m+m^2=-2m-1+m^2\)
\(\Leftrightarrow\)\(2m+2m+m^2-m^2=-1-1\)
\(\Leftrightarrow\)\(4m=0\)
\(\Leftrightarrow\)\(m=0\)
Vậy \(m=0\)
Chúc bạn học tốt ~
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(P\left(1\right)=Q\left(-1\right)\)
\(\Leftrightarrow1^2+2m+m^2=\left(-1\right)^2+\left(2m+1\right)\cdot\left(-1\right)+m^2\)
\(\Leftrightarrow m^2+2m+1=m^2-2m-1+1\)
=>2m+1=-2m
=>4m=-1
hay m=-1/4
![](https://rs.olm.vn/images/avt/0.png?1311)
P(1)=12+2.m.1+m2=Q(-1)=(-1)2+(2m+1).(-1)+m2
=>1+2m+m2=1+(2m+1).(-1)+m2
=>2m=(2m+1).(-1)
=>2m=-2m-1
=>2m+2m=-1
=>4m =-1
=>m =\(\dfrac{-1}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)