Question

[ngoc thach nguyen]

Cho biểu thức 

M=\(\frac{2x^2}{8+2x-x^2}\)+\(\frac{x+4}{x+2}\)-\(\frac{x+2}{4-x}\)

aRut gon

b.Tìm x để M có giá trị nguyên âm

Answer 1

[KAl(SO4)2·12H2O]

Mình lười nghĩ nên chúng ta dùng tool :)))

\(\frac{2x^2}{8+2x-x^2}+\frac{x+4}{x-2}-\frac{x+2}{4-x}\)

\(=\frac{4x^3-20x^2-8x+96}{x^4-4x^3-12x^2+32x+64}\)

\(=\frac{4\left(x+3\right)\left(x-3\right)\left(x-4\right)}{\left(x+2\right)\left(x+2\right)\left(x-4\right)\left(x-4\right)}\)

\(=\frac{4\left(x-3\right)}{\left(x+2\right)\left(x-4\right)}\)