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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(\left(x+2\right)^2=0\)
\(\Leftrightarrow x+2=0\)
\(\Leftrightarrow x=-2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{-3}{4}\left(15+\dfrac{2}{3}+24+\dfrac{1}{3}\right)=\dfrac{-3}{4}\cdot40=-30\)
b: \(=\dfrac{3}{8}\left(27+\dfrac{1}{5}-3-\dfrac{1}{5}\right)+19=\dfrac{3}{8}\cdot24+19=9+19=28\)
c: \(=\dfrac{7}{10}\cdot\dfrac{4}{5}+\dfrac{4}{5}\cdot\dfrac{3}{10}=\dfrac{4}{5}\)
d: \(=\dfrac{4}{15}+\dfrac{11}{15}+\dfrac{7}{11}+\dfrac{4}{11}-3.25=2-3.25=-1.25\)
f: \(=\dfrac{3}{5}\left(16+\dfrac{1}{4}-6-\dfrac{1}{4}\right)+\left|\dfrac{15-16}{10}\right|\)
\(=\dfrac{3}{5}\cdot10+\dfrac{1}{10}=6+\dfrac{1}{10}=\dfrac{61}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>1/3:x=-3/4-2/3=-9/12-8/12=-17/12
=>x=-1/3:17/12=-1/3*12/17=-12/51=-4/17
b: =>5/3x+1/2=1/7
=>5/3x=-5/10
=>x=-5/10:5/3=-5/10*3/5=-3/10
c: =>x+2/5=11/12-2/3=11/12-8/12=3/12=1/4
=>x=1/4-2/5=5/20-8/20=-3/20
g: =>3căn x=5
=>căn x=5/3
=>x=25/9
h: =>-5x=2/5-3/4=8/20-15/20=-13/20
=>x=13/20:5=13/100
k: =>3x-7=0 hoặc x^2-1/4=0
=>\(x\in\left\{\dfrac{7}{3};\dfrac{1}{2};-\dfrac{1}{2}\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
b: Xét ΔHIM và ΔHKM có
HI=HK
HM chung
IM=KM
Do đó: ΔHIM=ΔHKM