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\(H_2SO_4+3H_2S->4S+4H_2O\)
Chất oxi hóa: H2SO4
Chất khử: H2S
S+6 + 6e --> S0 | x1 |
S-2 -2e --> S0 | x3 |
\(S+2HNO_3->H_2SO_4+2NO\)
Chất oxi hóa: HNO3
Chất khử: S
S0 - 6e --> S+6 | x1 |
N+5 + 3e --> N+2 | x2 |
\(2KClO_3->2KCl+3O_2\)
Cl+5+6e-->Cl-1 | x2 |
2O3-2 -12e --> 3O20 | x1 |
\(3I_2+10HNO_3->6HIO_3+10NO+2H_2O\)
Chất oxi hóa: HNO3
Chất khử: I2
I20 -10e --> 2I+5 | x3 |
N+5 + 3e --> N+2 | x10 |
![](https://rs.olm.vn/images/avt/0.png?1311)
Bạn xem lại PT 1 và 3 nhé.
\(\overset{0}{Al}+H\overset{+5}{N}O_3\rightarrow\overset{+3}{Al}\left(NO_3\right)_3+\overset{0}{N_2}+H_2O\)
\(\overset{0}{Al\rightarrow}\overset{+3}{Al}+3e|\times10\)
\(2\overset{+5}{N}+10e\rightarrow\overset{0}{N_2}|\times3\)
⇒ 10Al + 36HNO3 → 10Al(NO3)3 + 3N2 + 18H2O
\(\overset{^{+2y/x}}{Fe_x}O_y+H\overset{+5}{N}O_3\rightarrow\overset{+3}{Fe}\left(NO_3\right)_3+\overset{+4}{N}O_2+H_2O\)
\(\overset{^{+2y/x}}{Fe_x}\rightarrow x\overset{+3}{Fe}+\left(3x-2y\right)e|\times1\)
\(\overset{+5}{N}+e\rightarrow\overset{+4}{N}|\times\left(3x-2y\right)\)
⇒ FexOy + (6x-2y)HNO3 → xFe(NO3)3 + (3x-2y)NO2 + (3x-y)H2O
![](https://rs.olm.vn/images/avt/0.png?1311)
\(CH_3C^{-1}H_2OH+Cr^{+7}_2O_7+H^+\rightarrow CH_3C^{+1}HO+Cr^{3+}+H_2O\)
\(C^{-1}\rightarrow C^{+1}+2e|\times4\)
\(2Cr^{+7}+8e\rightarrow2Cr^{+3}|\times1\)
→ \(4CH_3CH_2OH+Cr_2O_7+6H^+\rightarrow4CH_3CHO+2Cr^{+3}+7H_2O\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án:
a) \(H_2O_2+MnO_2\rightarrow H_2O+O_2+MnO\)
b) \(2NaOH\underrightarrow{\text{đpnc}}2Na+H_2+O_2\)
~HT~
TL
a)\(H_2O_2+MnO_2\rightarrow H_2O+O_2+MnO\)
b)\(2NaOH|\underrightarrow{đpnc}2Na+H_2+O_2\)
HT
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\(NH_3+CuO\rightarrow Cu+N_2O+H_2O\)
\(2N^{-3}\rightarrow2N^{+1}+8e|\times1\)
\(Cu^{+2}+2e\rightarrow Cu^0|\times4\)
⇒ 2NH3 + 4CuO → 4Cu + N2O + 3H2O
\(CO+Fe_2O_3\underrightarrow{t^o}Fe_3O_4+CO_2\)
\(C^{+2}\rightarrow C^{+4}+2e|\times1\)
\(3Fe^{+3}+1e\rightarrow3Fe^{+8/3}|\times2\)
\(\Rightarrow CO+3Fe_2O_3\underrightarrow{t^o}CO_2+2Fe_3O_4\)