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Ư(60) = {1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 10 ; 12 ; 15 ; 20 ; 30 ; 60}
Ư(80) = {1 ; 2 ; 4 ; 5 ; 8 ; 10 ; 16 ; 20 ; 40 ; 80}
ƯC(60;80) = {1 ; 2 ; 4 ; 5 ; 10 ; 20}
k nha
Ư(60)={1;2;3;4;5;6;10;12;15;20;30;60}
Ư(80)={1;2;4;5;8;10;16;20;40;80}
ƯC(60,80)={1,2,4,5,10,20}
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2,Ư\left(8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\\ Ư\left(11\right)=\left\{-11;-1;1;11\right\}\\ Ư\left(19\right)=\left\{-19;-1;1;19\right\}\\ Ư\left(28\right)=\left\{-28;-14;-7;-4;-2;-1;1;2;4;7;14;28\right\}\)
3.
\(A,45=3^2\cdot5\) nên có \(\left(2+1\right)\left(1+1\right)=6\left(ước\right)\)
\(B,103=103\) nên có \(1+1=2\left(ước\right)\)
2. Ư(8) = {1; 2; 4; 8}
Ư(11) = {1; 11}
Ư(19) = {1; 19}
Ư(28) = {1; 2; 4; 7; 14; 28}
3. Ư(45) = {1; 3; 5; 9; 15; 45} \(\Rightarrow\) 45 có 6 ước
Ư(103) = {1; 103} \(\Rightarrow\) 103 có 2 ước
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ư(4)={-4;-2;-1;1;2;4}
Ư(6)={-6;-3;-2;-1;1;2;3;6}
Ư(13)={-13;-1;1;13}
Ư(1)={-1;1}
\(\text{Ư}_{\left(4\right)}=\text{ }\left\{1;-1;2;-2;4;-4\right\}\)
\(\text{Ư}_{\left(6\right)}=\text{ }\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
\(\text{Ư}_{\left(13\right)}=\text{ }\left\{1;-1;13;-13\right\}\)
\(\text{Ư}_{\left(1\right)}=\text{ }\left\{1;-1\right\}\)
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