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\(\frac{1994.1993-1992.1993}{1992.1993+1994.7+1986}\)\(=\frac{\left(1994-1992\right).1993}{1992.1993+1992.7+2.7+1986}\)\(=\frac{2.1993}{1992.\left(1993+7\right)+14+1986}\)
\(=\frac{2.1993}{1992.2000+2000}\)\(=\frac{2.1993}{2000.\left(2000+1\right)}\)\(=\frac{2.1993}{2000.2001}\)\(=\frac{2.1993}{2.1000.2001}\)\(=\frac{1993}{1000.2001}=\frac{1993}{2001000}\)
câu 1
16 x 25 + 44 x 100
29 x 96 + 124 x 48
16 x 25 +44 x 100
=400 + 4400
=4800
29 x 96 +124 x 48
=2784 + 5952
=8736
Vậy 4800
8736
Câu 1: 6 x 25 + 44 x 100
29 x 96 + 142 x 48
Giải :(6 x 25) + (44 x 100) =
150 + 440 = 590
(29 x 96) + (142 x 48) =
2784 + 6816 = 9600
Câu 2 :1994 x 1993 - 1992 x 1993
1992 x 1993 + 1994 x 7 + 1986
Giải : (1994 x 1993) - (1992 x 1993) =
3 974 042 - 3 970 056 = 3986
(1992 x 1993) + (1994 x 7) + 1986 =
3 970 056 + 13 958 + 1986 = 3 986 000
Câu 3 : 399 x 45 + 55 x 399
1995 x 1996 - 1991 x 1995
\(\frac{1994\times1993-2}{1992+1992\times1994}=\frac{1994\times1992+1994-1}{1992+1992\times1994}=\frac{1994\times1992+1992}{1992+1992\times1994}=1\)
\(\frac{1994\cdot1993-2}{1992+1992-1994}\)
= \(\frac{1994\cdot1993-2}{1992+1992-1992-2}\)
= \(\frac{1994\cdot1993}{1992+1992-1992}=\frac{1994\cdot1993}{1992}=\frac{1987021}{996}.\)
\(A=1990\cdot1994\)
\(A=\left(1992-2\right)\cdot1994\)
\(A=1992\cdot1994-2\cdot1994\)
\(B=1992\cdot1992\)
\(B=\left(1994-2\right)\cdot1992\)
\(B=1994\cdot1992-2.1992\)
Ta có : B > A ( 2 x 1992 < 2 x 1994 )
a)
\(=\dfrac{4.4.25+4.11.4.25}{29.2.48+71.2.48}=\dfrac{400+400.11}{96.29+71.96}=\dfrac{400\left(1+11\right)}{96\left(29+71\right)}=\dfrac{400.12}{96.100}=\dfrac{2.2.100.12}{12.2.2.2.100}=\dfrac{1}{2}\)