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Ta có:\(x.\frac{1}{5}+x.\frac{4}{5}=2\)
=>\(x.\frac{1}{5}+\frac{4}{5}=2\)
=>\(x.\frac{5}{5}=2\)
=>\(x.1=2\)
=>\(x=2:1\)
=>\(x=2\)
\(\frac{13}{21}\)+\(\frac{15}{13}\)+\(\frac{14}{5}\)
=\(\frac{845}{1365}\)+\(\frac{1575}{1365}\)+\(\frac{3822}{1365}\)
=\(\frac{6242}{1365}\)
a,\(2-\frac{5}{7}+\frac{9}{21}\)
\(=2-\frac{154}{147}\)
\(=\frac{135}{147}\)
b, \(\frac{5}{8}\):\(3+\frac{25}{24}\)
\(=\frac{5}{24}+\frac{25}{24}\)
\(=\frac{30}{24}\)
Bài 2:
\(=\dfrac{28}{25}\cdot\dfrac{15}{7}\cdot5=\dfrac{75}{25}\cdot4=12\)
Bài 1:
a: \(x+\dfrac{7}{8}=\dfrac{13}{2}:4=\dfrac{13}{8}\)
nên x=13/8-7/8=6/8=3/4
b: \(x:\dfrac{5}{3}=\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18-10}{15}=\dfrac{8}{15}\)
nên \(x=\dfrac{8}{15}\cdot\dfrac{5}{3}=\dfrac{8}{9}\)
\(a,\left(13640-5537\right)\times8\)
\(=8103\times8=64824\)
\(b,27164+8470+1230=35634+1230=36864\)
\(\dfrac{3}{2}-\dfrac{4}{5}=\dfrac{15}{10}-\dfrac{8}{10}=\dfrac{7}{10}\)
\(\dfrac{2}{3}+\dfrac{1}{2}=\dfrac{4}{6}+\dfrac{3}{6}=\dfrac{7}{6}\)
\(\dfrac{1}{2}\times\dfrac{3}{7}=\dfrac{1\times3}{2\times7}=\dfrac{3}{14}\)
\(\dfrac{2}{3}:\dfrac{3}{2}=\dfrac{2}{3}\times\dfrac{2}{3}=\dfrac{4}{9}\)
a, a x 6 = 3 x 6 = 18
b, a + b = 4 + 2 = 6
c, b + a = 2 + 4 = 6
d, a - b = 8 - 5 = 3
e, m x n = 5 x 9 = 45
