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a) \(\frac{-2}{3}x+\frac{1}{5}=\frac{1}{10}\)
\(\Leftrightarrow\frac{-2}{3}x=\frac{1}{10}-\frac{1}{5}\)
\(\Leftrightarrow\frac{-2}{3}x=\frac{-1}{10}\)
\(\Leftrightarrow x=\frac{-1}{10}\div\frac{-2}{3}\)
\(\Leftrightarrow x=\frac{3}{20}\)
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1: =>x+1/2=0 hoặc 2/3-2x=0
=>x=-1/2 hoặc x=1/3
2: =>7/6x=5/2:3,75=2/3
=>x=2/3:7/6=2/3*6/7=12/21=4/7
3: =>2x-3=0 hoặc 6-2x=0
=>x=3 hoặc x=3/2
4: =>-5x-1-1/2x+1/3=3/2x-5/6
=>-11/2x-3/2x=-5/6-1/3+1
=>-7x=-1/6
=>x=1/42
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a)\(\frac{x+1}{3}=\frac{2}{6}\)
=> \(\frac{x+1}{3}=\frac{1}{3}\)
=> x + 1 = 1 => x = 0
b) \(\frac{4-x}{-5}=\frac{-5}{4-x}\)
=> (4 - x)2 = 25
=> (4 - x)2 = 52
=> 4 - x = 5 hoặc 4 - x = -5
=> x = -1 hoặc x = 9
c) \(\frac{3}{x+2}=\frac{5}{2x+1}\)
=> 3(2x + 1) = 5(x + 2)
=> 6x + 3 = 5x + 10
=> 6x + 3 - 5x - 10 = 0
=> 6x - 5x + 3 - 10 = 0
=> 6x - 5x = 7
=> x = 7
d) \(\frac{1}{2}=\frac{x+1}{3x}\)
=> 3x = 2(x + 1)
=> 3x = 2x + 2
=> 3x - 2x - 2 = 0
=> x - 2 = 0
=> x = 2
e) \(\frac{-3}{x+1}=\frac{4}{\left(2-2x\right)}\)
=> -3(2 - 2x) = 4(x + 1)
=> -6 + 6x = 4x + 4
=> -6 + 6x - 4x - 4 = 0
=> -10 + 2x = 0
=> 2x = 10
=> x = 5
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a) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\\ \dfrac{x}{5}+\dfrac{1}{2}=\dfrac{3}{5}\\ \dfrac{x}{5}=\dfrac{3}{5}-\dfrac{1}{2}\\ \dfrac{x}{5}=\dfrac{6}{10}-\dfrac{5}{10}\\ \dfrac{x}{5}=\dfrac{1}{10}\\ \dfrac{2x}{10}=\dfrac{1}{10}\\ \Rightarrow2x=1\\ x=1:2\\ x=0,5=\dfrac{1}{2}\)
b) \(x+\dfrac{3}{15}=\dfrac{1}{3}\\ x=\dfrac{1}{3}-\dfrac{3}{15}\\ x=\dfrac{5}{15}-\dfrac{3}{15}\\ x=\dfrac{2}{15}\)
c) \(x-\dfrac{12}{4}=\dfrac{1}{2}\\ x-3=\dfrac{1}{2}\\ x=\dfrac{1}{2}+3\\ x=\dfrac{1}{2}+\dfrac{6}{2}\\ x=\dfrac{7}{2}\)
d) \(\dfrac{1}{2}x+\dfrac{1}{2}=\dfrac{5}{2}\\ \dfrac{1}{2}x=\dfrac{5}{2}-\dfrac{1}{2}\\ \dfrac{1}{2}x=2\\ x=2:\dfrac{1}{2}\\ x=4\)
a. \(\dfrac{2x+5}{10}=\dfrac{6}{10}\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)
b. \(\dfrac{15x+3}{15}=\dfrac{5}{15}\Leftrightarrow15x=2\Leftrightarrow x=\dfrac{2}{15}\)
c. \(\dfrac{4x-12}{4}=\dfrac{2}{4}\Leftrightarrow4x=14\Leftrightarrow x=\dfrac{7}{2}\)
d. \(\dfrac{1+x}{2x}=\dfrac{5x}{2x}\Leftrightarrow-4x=-1\Leftrightarrow x=\dfrac{1}{4}\)
e. \(\dfrac{-4\left(2x-5\right)}{6\left(2x-5\right)}-\dfrac{2}{6\left(2x-5\right)}=\dfrac{9\left(2x-5\right)}{6\left(2x-5\right)}\)
\(\Leftrightarrow-8x+20-2=18x-45\)
\(\Leftrightarrow-26x=-63\Leftrightarrow x=\dfrac{63}{26}\)
a: =>2|2x-2/3|=-5/4
=>|2x-2/3|=-5/8(vô lý)
b: \(\Leftrightarrow-5x-1-\dfrac{1}{2}x+\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\)
=>-11/2x-2/3=3/2x-5/6
=>-7x=-5/6+2/3=-5/6+4/6=-1/6
=>x=1/42