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\(-8x^2y^2-12xy^3-4xy^2\)
\(=-4xy^2\left(2x+3y+1\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(12x³3y² - 8x²y² - x²y) : 4x²y - 2y(x - 1)
= 9xy - 2y - 1/4 - 2xy + 2y
= 7xy - 1/4
![](https://rs.olm.vn/images/avt/0.png?1311)
( - 12 x 4 y + 4 x 3 – 8 x 2 y 2 ) : ( - 4 x ) 2 = ( - 12 x 4 y ) : ( - 4 x 2 ) + ( 4 x 3 ) : ( - 4 x 2 ) – ( 8 x 2 y 2 ) : ( - 4 x 2 ) = 3 x 2 y – x + 2 y 2
Đáp án cần chọn là: D
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\(-8x^2y^2-12xy^2-4xy^2=-8x^2y^2-16xy^2\)
\(=-8xy^2\left(x+2\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có
( 3 x 5 y 2 + 4 x 3 y 2 – 8 x 2 y 2 ) : 2 x 2 y 2 = ( 3 x 5 y 2 : 2 x 2 y 2 ) + ( 4 x 3 y 2 : 2 x 2 y 2 ) – ( 8 x 2 y 2 : 2 x 2 y 2 ) = 3 2 x 3 + 2 x - 4
Đáp án cần chọn là: B
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,\\ 1,=15\left(x+y\right)\\ 2,=4\left(2x-3y\right)\\ 3,=x\left(y-1\right)\\ 4,=2x\left(2x-3\right)\\ 2,\\ 1,=\left(x+y\right)\left(2-5a\right)\\ 2,=\left(x-5\right)\left(a^2-3\right)\\ 3,=\left(a-b\right)\left(4x+6xy\right)=2x\left(2+3y\right)\left(a-b\right)\\ 4,=\left(x-1\right)\left(3x+5\right)\\ 3,\\ A=13\left(87+12+1\right)=13\cdot100=1300\\ B=\left(x-3\right)\left(2x+y\right)=\left(13-3\right)\left(26+4\right)=10\cdot30=300\\ 4,\\ 1,\Rightarrow\left(x-5\right)\left(x-2\right)=0\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\\ 2,\Rightarrow\left(x-7\right)\left(x+2\right)=0\Rightarrow\left[{}\begin{matrix}x=7\\x=-2\end{matrix}\right.\\ 3,\Rightarrow\left(3x-1\right)\left(x-4\right)=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=4\end{matrix}\right.\\ 4,\Rightarrow\left(2x+3\right)\left(2x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Đề là phân tích đa thức thành nhân tử hả bn
\(8x^2y^2-12y^3+16x^2\)
\(4\left(2x^2y^2-3y^3+4x^2\right)\)