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\(6\cdot x+9=15\)
\(\Rightarrow6\cdot x=15-9\)
\(\Rightarrow6\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{6}=1\)
_______________
\(43+2x=49\)
\(\Rightarrow2x=49-43\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
____________
\(x:2+5=11\)
\(\Rightarrow x:2=11-5\)
\(\Rightarrow x:2=6\)
\(\Rightarrow x=6\cdot2=12\)
______________
\(77-11x=0\)
\(\Rightarrow11x=77\)
\(\Rightarrow x=\dfrac{77}{11}\)
\(\Rightarrow x=7\)
_______________
\(12-4:x=8\)
\(\Rightarrow4:x=12-8\)
\(\Rightarrow4:x=4\)
\(\Rightarrow x=\dfrac{4}{4}=1\)
_____________
\(x:3+8=11\)
\(\Rightarrow x:3=11-8\)
\(\Rightarrow x:3=3\)
\(\Rightarrow x=3\cdot3=9\)
a: 6x+9=15
=>6x=6
=>x=1
b: 2x+43=49
=>2x=6
=>x=3
c: x:2+5=11
=>x:2=6
=>x=12
d: 77-11x=0
=>7-x=0
=>x=7
e: 12-4:x=8
=>4:x=4
=>x=1
f: x:3+8=11
=>x:3=3
=>x=9
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`@` `\text {Ans}`
`\downarrow`
\(\left(8x-16\right)\cdot\left(x-4^3\right)=0\)
\(\Rightarrow\) \(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}8x=16\\x=64+0\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}x=16\div8\\x=64\end{matrix}\right.\)
`\Rightarrow`\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)
Vậy, \(x\in\left\{2;64\right\}\)
(8\(x\) -16)(\(x-4^3\)) = 0
\(\left[{}\begin{matrix}8x-16=0\\x-4^3=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}8x=16\\x=64\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=64\end{matrix}\right.\)
Vậy \(x\in\) { 2; 64}
![](https://rs.olm.vn/images/avt/0.png?1311)
\(27+\left(43+11\right)-43-\left(27+11\right)\)
\(=27+43+11-43-27-11\)
\(=\left(27-27\right)+\left(43-43\right)+\left(11-11\right)\)
\(=0+0+0\)
\(=0\)
27+(43+11)-43-(27+11)
= 27 + 43 + 11 - 43 - 27 -11
= ( 27 - 27 ) + ( 43 - 43 ) + ( 11-11 )
= 0 + 0 + 0
=0
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\)
\(-18-x=-8+\left(13\right)\)
\(\Rightarrow-18-x=5\)
\(\Rightarrow x=-18-5=-23\)
\(b.\)
\(x-43=\left(57-x\right)-50\)
\(\Rightarrow x-43=57-x-50\)
\(\Rightarrow x+x=43+57-50\)
\(\Rightarrow2x=50\)
\(\Rightarrow x=25\)
\(c.\)
\(-4\left(2x+9\right)-\left(-8x+3\right)-\left(x+13\right)=0\)
\(\Rightarrow-8x-36+8x-3-x-13=0\)
\(\Rightarrow-x-52=0\)
\(\Rightarrow-x=52\)
\(\Rightarrow x=-52\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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D = 3\(\dfrac{1}{2}\) \(\times\) \(\dfrac{12}{43}\) + \(\dfrac{49}{14}\) \(\times\) \(\dfrac{31}{43}\) + \(\dfrac{11}{2}\)
D = \(\dfrac{7}{2}\) \(\times\) \(\dfrac{12}{43}\) + \(\dfrac{7}{2}\) \(\times\) \(\dfrac{31}{43}\) + \(\dfrac{11}{2}\)
D = \(\dfrac{7}{2\times43}\) \(\times\) (12 + 31) + \(\dfrac{11}{2}\)
D = \(\dfrac{7}{2\times43}\) \(\times\) 43 + \(\dfrac{11}{2}\)
D = \(\dfrac{7}{2}\) + \(\dfrac{11}{2}\)
D = 9
D = 3 và 1/2 x 12/43 + 49/14 x 31/43 + 11/2
= 7/2 x 12/43 + 49/14 x 31/43 + 11/2
= 42/43 + 217/36 + 11/2
=9
# https://lazi.vn/user/tnsociu
\(-8x-\left(-11\right)=43\)
\(\Leftrightarrow-8x=43-11\)
\(\Leftrightarrow-8x=32\)
\(\Leftrightarrow x=\dfrac{32}{-8}\)
\(\Leftrightarrow x=-4\)
-8.x-(-11)=43
-8.x =43+(-11)
-8.x =32
x =32:(-8)
x =-4