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`a)145×16+145×83+123×22`
`=145xx(16+83)+123xx22`
`=145xx99+123xx22`
`=145xx9xx11+123xx2xx11`
`=1305xx11+246xx11`
`=(1305+246)xx11`
`=1551xx11`
`=`\(17061\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(7\times\left(18-a\right)-56=7\)
\(7\times\left(18-a\right)=7+56\)
\(7\times\left(18-a\right)=63\)
\(18-a=63:7\)
\(18-a=9\)
\(a=18-9\)
\(a=9\)
______
b) \(145-5\times\left(a+8\right)=25\)
\(5\times\left(a+8\right)=145-25\)
\(5\times\left(a+8\right)=120\)
\(a+8=120:5\)
\(a+8=24\)
\(a=24-8\)
\(a=16\)
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145,46 - 356,64 : 16 + 37,009
= 145,46 - 22,29 + 37,009
= 123,35 + 37,009
= 160,359
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c) \(\left(11+12+13+...+19\right).\left(6.8-48\right)=\left(11+12+13+...+19\right).\left(48-48\right)\)
\(=\left(11+12+13+...+19\right).0\)
\(=0\)
Hok "tuốt" nha^^
b) \(\left(500.9-250.18\right).\left(1+2+3+...+9\right)=\left(250.2.9-250.18\right).\left(1+2+...+9\right)\)
\(=\left(250.18-250.18\right).\left(1+2+3+...+9\right)\)
\(=0.\left(1+2+3+...+9\right)\)
\(=0\)
Hok tốt nha^^ (lần 2)
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a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)
\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)
b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)
\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)
c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)
\(7x-16=145\\ =>7x=145+16\\ =>7x=161\\ =>x=161:7=23\)
\(7x-16=145\)
\(\Rightarrow7x=145+16\)
\(\Rightarrow7x=161\)
\(\Rightarrow x=161:7\)
\(\Rightarrow x=23\)