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b: =>15-x=-10
hay x=25
a: =>-2x+17=9
=>-2x=-8
hay x=4
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x+17=9
=>-2x=-8
hay x=4
b: =>15-x=-10
hay x=25
c: =>7x=-4
hay x=-4/7
d: =>\(9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
g: \(\Leftrightarrow2x-4+5⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{3;1;7;-3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x=9-17=-8
hay x=4
b: =>15-x=-10
hay x=25
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\)\(7x-2x=6^{17}:6^{15}+44:11\)
\(\Leftrightarrow5x=6^2+4\)
\(\Leftrightarrow5x=36+4\)
\(\Leftrightarrow5x=40\)
\(\Leftrightarrow x=40:5\)
\(\Leftrightarrow x=8\)
\(b.\)\(9^{x-1}=9\)
\(\Leftrightarrow9^x:9=9\)
\(\Leftrightarrow9^x=81\)
\(\Leftrightarrow9^x=9^2\)
\(\Leftrightarrow x=2\)
\(c.\)\(\left|x-5\right|=7-\left(-3\right)\)
\(\Leftrightarrow\left|x-5\right|=7+3\)
\(\Leftrightarrow\left|x-5\right|=10\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=10\\x-5=-10\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}\)
\(d.\)\(\left|x-5\right|=\left|-7\right|\)
\(\Leftrightarrow\left|x-5\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)
\(e.\)\(\left|x\right|-5=3\)
\(\Leftrightarrow\left|x\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)
\(g.\)\(15-2\left|x\right|=13\)
\(\Leftrightarrow2\left|x\right|=15-13=2\)
\(\Leftrightarrow\left|x\right|=2:2=1\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
\(h.\)\(\left|x-2\right|=0\)
\(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=0+2\)
\(\Leftrightarrow x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5x + x = 39 - 311 : 39
6x = 39 - 32
6x = 39 - 9
6x = 30
x = 30 : 6
x = 5
7x - x = 521 : 519 + 3 . 22 - 70
6x = 52 + 3 . 4 - 1
6x = 25 + 12 - 1
6x = 37 - 1
6x = 36
x = 36 : 6
x = 6
7x - 2x = 617 : 615 + 44 : 11
5x = 62 + 4
5x = 36 + 4
5x = 40
x = 40 : 5
x = 8
0 : x = 0
\(\Rightarrow\)x \(\in\) N*
3x = 9
3x = 32
\(\Rightarrow\) x = 2
4x = 64
4x = 43
\(\Rightarrow\)x = 3
2x = 16
2x = 24
\(\Rightarrow\)x = 4
9x-1 = 9
9x-1 = 91
\(\Rightarrow\)x - 1 = 1
x = 1 + 1
x = 2
x4 = 16
24 = 16
\(\Rightarrow\)x = 2
2x : 25 = 1
2x : 25 = 20
\(\Rightarrow\) 25 : 25 = 20
\(\Rightarrow\)x = 5
1) \(5x+x=39-3^{11}:3^9\)
\(6x=39-3^2\)
\(6x=39-9\)
\(6x=30\)
\(x=30:6\)
\(x=5\)
2) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)
\(6x=5^2+3.4-1\)
\(6x=25+12-1\)
\(6x=37-1\)
\(6x=36\)
\(x=36:6\)
\(x=6\)
3) \(7x-2x=6^{17}:6^{15}+44:11\)
\(\left(7-2\right)x=6^2+4\)
\(5x=36+4\)
\(5x=40\)
\(x=40:5\)
\(x=8\)
4) \(0:x=0\)
\(\Rightarrow x\in N\)*
5) \(3^x=9\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
6) \(4^x=64\)
\(4^x=4^3\)
\(\Rightarrow x=3\)
7) \(2^x=16\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
8) \(9^{x-1}=9\)
\(\Rightarrow x-1=1\)
\(x=1+1\)
\(x=2\)
9) \(x^4=16\\\)
\(x^4=2^4\)
\(\Rightarrow x=2\)
10) \(2^x:2^5=1\)
\(2^x:32=1\)
\(2^x=32.1\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
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7x-x=521:519+3.22-70
=> 6x = 5^2 + 12 -1
=> 6x = 36
=> x = 36/6 = 6
Kết quả 6
Học tốt
ko ghi lại đề
ta có 2 TH
TH1: TH2
\(7x-15=0\) \(x1-\frac{1}{9}=0\)
\(7x=15\) \(x1=\frac{1}{9}\)
\(x=\frac{15}{7}\) \(x=\frac{1}{9}\)
Vậy \(x\in\left\{\frac{15}{7};\frac{1}{9}\right\}\)
(7x-15).(x1-1\9)=0
<=>(7x-15).(x-1/9)=0
\(\orbr{\begin{cases}7x-15=0\\x-\frac{1}{9}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}7x=15\\x=\frac{1}{9}\end{cases}}}\Leftrightarrow\orbr{\begin{cases}x=\frac{15}{7}\\x=\frac{1}{9}\end{cases}}\)
\(\text{vậy }x\in\left\{\frac{15}{7};\frac{1}{9}\right\}\)