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\(a.\)\(7x-2x=6^{17}:6^{15}+44:11\)
\(\Leftrightarrow5x=6^2+4\)
\(\Leftrightarrow5x=36+4\)
\(\Leftrightarrow5x=40\)
\(\Leftrightarrow x=40:5\)
\(\Leftrightarrow x=8\)
\(b.\)\(9^{x-1}=9\)
\(\Leftrightarrow9^x:9=9\)
\(\Leftrightarrow9^x=81\)
\(\Leftrightarrow9^x=9^2\)
\(\Leftrightarrow x=2\)
\(c.\)\(\left|x-5\right|=7-\left(-3\right)\)
\(\Leftrightarrow\left|x-5\right|=7+3\)
\(\Leftrightarrow\left|x-5\right|=10\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=10\\x-5=-10\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=15\\x=-5\end{cases}}\)
\(d.\)\(\left|x-5\right|=\left|-7\right|\)
\(\Leftrightarrow\left|x-5\right|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)
\(e.\)\(\left|x\right|-5=3\)
\(\Leftrightarrow\left|x\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x=8\\x=-8\end{cases}}\)
\(g.\)\(15-2\left|x\right|=13\)
\(\Leftrightarrow2\left|x\right|=15-13=2\)
\(\Leftrightarrow\left|x\right|=2:2=1\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
\(h.\)\(\left|x-2\right|=0\)
\(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=0+2\)
\(\Leftrightarrow x=2\)
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\(\left(x-7\right)\left(x+2019\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-7=0\\x+2019=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=7\\x=-2019\end{cases}}\)
\(9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Leftrightarrow-16=7-x-25-7\)
\(\Leftrightarrow-x=-16+25\)
\(\Leftrightarrow-x=9\)
\(\Leftrightarrow x=-9\)
\(2\left(4x-2x\right)-7x=15\)
\(\Leftrightarrow4x-7x=15\)
\(\Leftrightarrow x=-5\)
a ) 9 - 25 = ( 7 - x ) - ( 25 + 7 )
9 - 25 = 7 - x - 25 - 7
9 - 25 - 7 + 25 + 7 = -x
9 = - x
=> x = -9
Vậy x = -9
b) 2 . ( 4x - 2x ) - 7x = 15
8x - 4x - 7x = 15
-3x = 15
x = 15 : ( - 3 )
x = -5
Vậy x = -5
c ) ( x - 7 ). ( x + 2019 ) = 0
=> x - 7 = 0 hoặc x + 2019 = 0
=> x = 7 hoặc x = - 2019
vậy x \(\in\){ 7 ; -2019 }
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a ) \(-5\times\left(-x+7\right)-3\times\left(-x-5\right)=-4\times\left(12-x\right)+48\)
\(\Leftrightarrow5x-35+3x+15=-48+4x+48\)
\(\Leftrightarrow5x-3x+4x=35-15-48+48\)
\(\Leftrightarrow2x=20\)
\(\Leftrightarrow x=10\)
b ) \(-2\times\left(15-3x\right)-4\times\left(-7x+8\right)=-5-9\times\left(-2x+1\right)\)
\(\Leftrightarrow-30+6x-28x-32=-5+18x-9\)
\(\Leftrightarrow6x-28x-18x=30+32-5-9\)
\(\Leftrightarrow-40x=48\)
\(\Leftrightarrow x=-1.2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b: =>15-x=-10
hay x=25
a: =>-2x+17=9
=>-2x=-8
hay x=4
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
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a: =>-2x+17=9
=>-2x=-8
hay x=4
b: =>15-x=-10
hay x=25
c: =>7x=-4
hay x=-4/7
d: =>\(9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
g: \(\Leftrightarrow2x-4+5⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{3;1;7;-3\right\}\)
a) 2x + 1 = 7x - 9
2x - 7x = -9 -1
-5x = -10
x= -10 : -5 = 2
b) x . ( x - 1 ) = 0
th1 : x= 0 th2 : x-1 =0
x= 0 + 1 = 1
c) x - 15 = 7 - x
x + x = 7 + 15
2x = 22
x = 22 : 2
x= 11
Vậy ...................