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b)\(1-\left(3\frac{2}{5}+x-4\frac{7}{15}\right):5\frac{2}{5}=0\)
=>\(1-\left(\frac{17}{5}+x-\frac{67}{15}\right)=0\)\
=>\(\frac{17}{5}+x-\frac{67}{15}=1\)
=>\(\left(\frac{17}{5}-\frac{67}{15}\right)+x=1\)
=>(\(\frac{51-67}{15}\))+x=1
=>\(\frac{-16}{15}+x=1\)
=>x=\(1-\frac{-16}{15}\)
=>x=\(\frac{31}{15}=2\frac{1}{15}\)
a)|2x-3|-2=5
=>|2x-3|=5+2
=>|2x-3|=7
=>2x-3=±7
Th1:2x-3=7
=>2x=10
=>x=5
Th2:2x-3=-7
=>2x=-10
=>x=-5
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a) 2.x - 4 = 11
=> 2x = 11 + 4
=> 2x = 15
=> x = 15/2 (loại vì x thuộc Z)
b) 3|2x - 5| + 3 = 24
=> 3|2x - 5| = 24 - 3
=> 3|2x - 5| = 21
=> |2x - 5| = 21 : 3
=> |2x - 5| = 7
=> 2x - 5 = 7 => 2x = 12 => x = 6
hoặc 2x - 5 = -7 => 2x = -2 => x = -1
c) |2x - 3| ≤ 5
=> -5 \(\le\)2x - 3 \(\le\)5
=> -5 + 3 \(\le\)2x \(\le\)5 + 3
=> -2 \(\le\)2x \(\le\)8
=> -1 <= x <= 4, mà x thuộc Z
=> x \(\in\){-1;0;1;2;3;4}
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\(\frac{x-5}{2}+\frac{3}{5}=\frac{1-2x}{5}\)
\(\frac{x-5}{2}+\frac{3}{5}=\frac{1}{5}+\frac{-2x}{5}\)
\(\frac{x-5}{2}-\frac{-2x}{5}=\frac{1}{5}-\frac{3}{5}\)
\(\frac{x-5}{2}-\frac{-2x}{5}=\frac{-2}{5}\)
\(\frac{x-5}{2}+\frac{2x}{5}=\frac{-2}{5}\)
\(\frac{5\left(x-5\right)}{10}+\frac{2\left(2x\right)}{10}=\frac{-4}{10}\)
\(\frac{5x-25}{10}+\frac{4x}{10}=\frac{-4}{10}\)
\(\Rightarrow5x-25+4x=-4\)
\(\left(5x+4x\right)-25=-4\)
\(9x-25=-4\)
\(9x=-4+25\)
\(9x=21\)
\(x=\frac{7}{3}\)
\(x=2\frac{1}{3}\)
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a) \(\left(3\frac{2}{5}-2x\right).1\frac{2}{3}=5\frac{1}{7}\)
\(\left(\frac{17}{5}-2x\right).\frac{5}{3}=\frac{36}{7}\)
\(\left(\frac{17}{5}-2x\right)=\frac{36}{7}:\frac{5}{3}\)
\(\left(\frac{17}{5}-2x\right)=\frac{108}{35}\)
\(2x=\frac{17}{5}-\frac{108}{35}=\frac{11}{35}\)
\(x=\frac{11}{35}:2\)
\(x=\frac{11}{35}.\frac{1}{2}=\frac{11}{70}\)
Đúng ko z Kỳ Tỉ
Trả lời0 Đánh dấu5 giây trước (16:57)
tìm x biết
a) ($3\frac{2}{5}$325 -2x).$1\frac{2}{3}$123 =$5\frac{1}{7}$517
Toán lớp 6
a) (\(3\frac{2}{5}\) - 2x ) . \(1\frac{2}{3}\) = \(5\frac{1}{7}\)
<=> \(\frac{17}{3}\) - \(\frac{10}{3}x\) = \(5\frac{1}{7}\)
<=> \(\frac{10}{3}x\) = \(\frac{11}{21}\)
<=> \(x\) = \(\frac{11}{70}\)
b) \(\frac{x}{3}\) = \(\frac{5}{-27}\)
<=> - 27 x = 15
<=> x= \(-\frac{5}{9}\)
OK
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a)\(\frac{1}{3}x+\frac{2}{5}\left(x-1\right)=0\)
\(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}=0\)
\(\frac{11}{15}x-\frac{2}{5}=0\)
\(\frac{11}{15}x=\frac{2}{5}\)
\(x=\frac{6}{11}\)
b)(2x-3)(6-2x)=0
=>2x-3=0 hoặc 6-2x=0
=>x=3/2 hoặc x=3
c)\(x:\frac{3}{4}+\frac{1}{4}=-\frac{2}{3}\)
\(x:\frac{3}{4}=-\frac{11}{12}\)
\(x=-\frac{11}{16}\)
d)\(-\frac{2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)
\(-\frac{2}{3}-\frac{2}{3}x+\frac{5}{3}=\frac{3}{2}\)
\(-\frac{2}{3}x+1=\frac{3}{2}\)
\(-\frac{2}{3}x=\frac{1}{2}\)
\(x=-\frac{3}{4}\)
\(60\%x+\frac{2}{3}x=\frac{1}{3}.6\frac{1}{3}\)
\(\frac{3}{5}x+\frac{2}{3}x=\frac{19}{9}\)
\(\frac{19}{15}x=\frac{19}{9}\)
\(x=\frac{5}{3}\)
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d)2/5+3/5(3x-3,7)=-53/10
3/5(3x-3,7)=-53/10-2/5
3/5(3x-3,7)=-57/10
3x-3,7 =-57/10:3/5
3x-3,7 =-19/2
3x =-19/2+37/10
3x =-29/5
x =-29/5:3
x =-29/15
e)(2x-1/3)+5/6=1
2x-1/3 =1-5/6
2x-1/3 =1/6
2x =1/6+1/3
2x =1/2
x =1/2:2
x =1/4
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\(a,3\left(x+1\right)-2=4\)
\(\Leftrightarrow3\left(x+1\right)=6\)
\(\Leftrightarrow x+1=2\)
\(\Leftrightarrow x=1\)
Vậy x=1
Các câu còn lại lm tương tự nhé
\(3\left(x+1\right)-2=4\)
<=> \(3x+3-2=4\)
<=> \(3x=3\)
<=> \(x=1\)
\(5\left(x-2\right)+20=45\)
<=> \(5x-10=25\)
<=> \(x=7\)
\(700-7\left(x+2\right)=140\)
<=> \(7x+14=560\)
<=> \(7x=546\)
<=> \(x=78\)
\(200-5\left(2x+4\right)=100\)
<=> \(10x+20=100\)
<=> \(x=8\)
\(5\left(2x-4\right)+150=250\)
<=> \(10x-20=100\)
<=> \(x=12\)
học tốt
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Sửa đề một chút nhé !
52x + 3 + 52 = 153
52x + 3 + 25 = 153
52x + 28 = 153
52x = 153 - 28
52x = 125
52x = 53
\(\Rightarrow\)2x = 3
\(\Rightarrow\)x = 1,5