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a) 5.22 + (x + 3) = 52
5.4 + (x + 3) = 25
20 + (x + 3) = 25
x + 3 = 25 – 20
x + 3 = 5
x = 5 – 3 = 2
b) 23 + (x – 32) = 53 - 43
8 + (x – 9) = 125 – 64
8 + (x – 9) = 61
x – 9 = 61 – 8
x – 9 = 53
x = 53 + 9 = 62
a) \(5.2^2+\left(x+3\right)=5^2\)
\(x+3=5^2-5.2^2\)
\(x+3=25-20\)
\(x+3=5\)
\(x=2\)
b) \(2^3+\left(x-3^2\right)=5^3-4^3\)
\(8+\left(x-9\right)=125-64\)
\(x-9=53\)
\(x=62\)
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a: \(\left(-150\right):\left(-5\right)-2\cdot5^2\)
\(=\dfrac{150}{5}-2\cdot25\)
=30-50
=-20
b: \(2040-\left[10\cdot\left(4^3-46\right):18+2^3\right]\cdot2022^0\)
\(=2040-\left[10\cdot\left(64-46\right):18+8\right]\)
\(=2040-\left[10\cdot18:18+8\right]\)
\(=2040-10-8=2030-8=2022\)
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a) \(S=1+2+2^2+..+2^{2022}\)
\(2S=2+2^2+2^3+...+2^{2023}\)
\(2S-S=2+2^2+2^3+...+2^{2023}-1-2-2^2-...-2^{2022}\)
\(S=2^{2023}-1\)
b) \(S=3+3^2+3^3+...+3^{2022}\)
\(3S=3^2+3^3+...+3^{2023}\)
\(3S-S=3^2+3^3+....+3^{2023}-3-3^2-...-3^{2022}\)
\(2S=3^{2023}-3\)
\(\Rightarrow S=\dfrac{3^{2023}-3}{2}\)
c) \(S=4+4^2+4^3+...+4^{2022}\)
\(4S=4^2+4^3+...+4^{2023}\)
\(4S-S=4^2+4^3+...+4^{2023}-4-4^2-...-4^{2022}\)
\(3S=4^{2023}-4\)
\(S=\dfrac{4^{2023}-4}{3}\)
d) \(S=5+5^2+...+5^{2022}\)
\(5S=5^2+5^3+...+5^{2023}\)
\(5S-S=5^2+5^3+...+5^{2023}-5-5^2-...-5^{2022}\)
\(4S=5^{2023}-5\)
\(S=\dfrac{5^{2023}-5}{4}\)
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a ) x = 19 20 x = 19 20 b ) x = 83 12 x = − 37 12
c ) x = 31 12 x = − 25 12 d ) x = 13 4 x = − 7 12
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a) x − 2 = − 3 5 + 2 3 ⇔ x − 2 = 19 15 ⇔ x − 2 = 19 15 x − 2 = − 19 15 ⇔ x = 49 15 x = 11 15
b) x − 4 3 = 1 6 + 5 3 − 1 2 + 7 12 ⇔ x − 4 3 = 23 12 ⇔ x − 4 3 = 23 12 x − 4 3 = − 23 12 ⇔ x = 13 4 x = − 7 12
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\frac{7}{3\times13}+\frac{7}{13\times23}+...+\frac{7}{53\times63}\)
\(A=\frac{7}{10}.\left[\left(\frac{1}{3}-\frac{1}{13}\right)+\left(\frac{1}{13}-\frac{1}{23}\right)+....+\left(\frac{1}{53}-\frac{1}{63}\right)\right]\)
\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+....+\frac{1}{53}-\frac{1}{63}\right)\)
\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{63}\right)\)
\(A=\frac{7}{10}.\frac{20}{63}\)
\(A=\frac{2}{9}\)
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a) 4 ; 8 ; 16 ; 32 ; 64
b) 9 ; 27 ; 81 ; 243
c) 16 ; 64 ; 256
d) 25 ; 125
Chúc bạn học tốt!! ^^
a) \(2^2=4\)
\(2^3=8\)
\(2^4=16\)
\(2^5=32\)
\(2^6=64\)
b) \(3^2=3\)
\(3^3=27\)
\(3^4=81\)
\(3^5=243\)
c) \(4^2=16\)
\(4^3=64\)
\(4^4=256\)
d) \(5^2=25\)
\(5^3=125\)
a ,
5.22 +( x + 3) = 5^2
TH1 : nếu là : 5^2
ta có :
5.22 +( x + 3) = 5^2
(=) 20 + ( x + 3 ) = 5^2
(=) x + 3 = 32
(=) x = 29
a) 5.22 + (x + 3) = 52
<=> 20 + x + 3 = 25
<=> x + 3 = 5
<=> x = 2
b) 23 + (x - 32) = 53 - 43
<=> 8 + (x - 9) = 61
<=> x - 1 = 61
<=> x = 62