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\(\frac{89}{5}+\frac{3}{4}x\frac{1}{3}x\frac{4}{5}=\frac{89}{5}+\frac{1}{5}=\frac{90}{5}=18\)
Trả lời:
\(194-24\div\left(44x-3\right)-25=145\)
\(\Leftrightarrow194-24\div\left(44x-3\right)=170\)
\(\Leftrightarrow24\div\left(44x-3\right)=24\)
\(\Leftrightarrow44x-3=1\)
\(\Leftrightarrow44x=4\)
\(\Leftrightarrow x=\frac{1}{11}\)
Vậy \(x=\frac{1}{11}\)
\(x\times\frac{1}{3}\div\frac{2}{9}-x\div5=1\frac{2}{5}\)
\(\Leftrightarrow x\times\frac{1}{3}\times\frac{9}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{3}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\left(\frac{3}{2}-\frac{1}{5}\right)=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{13}{10}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{14}{13}\)
Vậy \(x=\frac{14}{13}\)
(x + 1) + (x + 2) + (x + 3) + ...+ (x + 89) = 571
=> 89x + (1 + 2 + 3 + ... + 89) = 571
=> 89x + 4005 = 571
=> 89x = -3434
=> x = -3434/89
(x + 1) + (x + 2) + (x + 3) + ...+ (x + 89) = 571
=> 89x + (1 + 2 + 3 + ... + 89) = 571
=> 89x + 4005 = 571
=> 89x = -3434
=> x = -3434/89
a, 10 - 2 x ( x - 1 ) = 44
2 x ( x - 1 ) = 10 - 44
2 x ( x - 1 ) = -34
x - 1 = -34 : 2
x - 1 = -17
x = -17 + 1
x = -16
Vậy x =-16
b, ( x + 2 ) x 3 - 10 = 5
( x + 2 ) x 3 = 5 + 10
( x + 2 ) x 3 = 15
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
Vậy x = 3
a) 4/9.x=25/18:2/3
4/9.x=25/18.3/2
4/9.x=75/36
x=75/36:4/9
x=75/36x4/9
x=675/144
b)x:4/5=25/8:5/4
x:4/5=25/8x4/5
x:4/5=100/40
x:4/5=5/2
x=5/2x4/5
x=20/10
x=2/1=2
c)22/5:x=44/5:5/2
22/5:x=44/5x2/5
22/5:x=88/25
x=88/25:22/5
x=88/25x22/5
x=440/550
x=4/5
h nk
A) X = 70,5 - ( 89,075 : 3,5 )
X = 70,5 - 25,45
X = 40,05
B) X = ( 67,8 : 1,5 ) + 20,5
X = 45,2 + 20,5
X = 65,7
\(\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3.4}+....+\frac{5}{x.\left(x+1\right)}=\frac{44}{9}\)
\(5.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{x.\left(x+1\right)}\right)=\frac{44}{9}\)
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{x}-\frac{1}{x+1}=\frac{44}{9}:5\)
\(1-\frac{1}{x+1}=\frac{44}{45}\)
\(\frac{1}{x+1}=1-\frac{44}{45}\)
\(\frac{1}{x+1}=\frac{1}{45}\)
=> x + 1 = 45
=> x = 45 - 1
=> x = 44
\(\frac{5}{3.4}+\frac{5}{4.5}+...+\frac{5}{88.89}=5\left(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{88.89}\right)\)
\(=5\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{88}-\frac{1}{89}\right)=5\left(\frac{1}{3}-\frac{1}{89}\right)=\frac{430}{267}\)